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Find the sum of squares of first 5 natural numbers.

hard Q9 of 15
Numerical Ability - Simplification & Approximation
Find the sum of squares of first 5 natural numbers.
A50
B60
C65
D55
Step-by-Step Solution
  1. Step 1: Recall the formula:

    Sum of squares = n(n+1)(2n+1)/6.
  2. Step 2: Compute for n = 5:

    (5 × 6 × 11) ÷ 6 = 330 ÷ 6 = 55.
  3. Final Answer:

    55 → Option D.
  4. Quick Check:

    1² + 2² + 3² + 4² + 5² = 1 + 4 + 9 + 16 + 25 = 55 ✅
Quick Trick: Use the formula n(n+1)(2n+1)/6 for squares.
Common Mistakes:
  • Forgetting the (2n+1) term in the numerator.
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