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Series-Based Approximation

Introduction

Series-based approximation problems test your ability to quickly simplify sums or products of sequences like arithmetic (AP), geometric (GP), or special series. Instead of calculating each term one by one, you use formulas or shortcuts to evaluate or approximate the series.

Pattern: Series-Based Approximation

Pattern

Key idea: Use standard series formulas (AP, GP, sum of squares, sum of cubes) or identify simple patterns to compute totals quickly.

  • AP sum formula: Sn = n/2 × (first term + last term)
  • Sum of first n natural numbers: n(n+1)/2
  • Sum of first n odd numbers:
  • Sum of first n even numbers: n(n+1)
  • GP sum formula: Sn = a(1-rn)/(1-r)

Step-by-Step Example

Question

Find the sum of the first 5 odd numbers: 1 + 3 + 5 + 7 + 9.

Options:

  • A) 25
  • B) 23
  • C) 27
  • D) 21

Solution

  1. Step 1: Recall the formula

    Sum of first n odd numbers = n².
  2. Step 2: Compute for n = 5

    Sum = 5² = 25.
  3. Final Answer:

    25 → Option A.
  4. Quick Check:

    Direct addition → 1 + 3 + 5 + 7 + 9 = 25 ✅

Quick Variations

1. Sum of first n even numbers = n(n+1).

2. Arithmetic series like 2 + 4 + 6 + … + 20.

3. Geometric series approximations when ratio < 1.

4. Using approximation when n is very large (e.g., sum of first 1000 natural numbers).

Trick to Always Use

  • Step 1 → Identify the type of series (AP, GP, odd, even, squares, cubes).
  • Step 2 → Apply the correct standard formula instead of adding term by term.
  • Step 3 → Use approximation if large n makes exact computation time-consuming.

Summary

Summary

  • Recognise the pattern quickly (odd, even, AP, GP).
  • Apply the shortcut formula instead of manual addition.
  • Use approximation when exact values aren’t required.
  • Always verify with a small example to confirm the formula.

Example to remember:
Use the AP formula Sn = n/2 × (first term + last term) for fast sums of arithmetic progressions; e.g., sum of first 100 natural numbers = 100×101/2 = 5050.

Practice

(1/5)
1. Find the sum of the first 6 odd numbers.
easy
A. 36
B. 30
C. 28
D. 32

Solution

  1. Step 1: Recall the formula

    Sum of first n odd numbers = n².
  2. Step 2: Compute for n = 6

    6² = 36.
  3. Final Answer:

    36 → Option A.
  4. Quick Check:

    1 + 3 + 5 + 7 + 9 + 11 = 36 ✅
Hint: n odd numbers always sum to n².
Common Mistakes: Adding terms manually and making mistakes.
2. Find the sum of the first 5 even numbers.
easy
A. 30
B. 25
C. 28
D. 32

Solution

  1. Step 1: Recall the formula

    Sum of first n even numbers = n(n+1).
  2. Step 2: Compute for n = 5

    5 × 6 = 30.
  3. Final Answer:

    30 → Option A.
  4. Quick Check:

    2 + 4 + 6 + 8 + 10 = 30 ✅
Hint: Sum of n even numbers = n(n+1).
Common Mistakes: Using formula for odd numbers instead of even.
3. Find the sum of the first 10 natural numbers.
easy
A. 50
B. 55
C. 60
D. 45

Solution

  1. Step 1: Recall the formula

    Sum of first n natural numbers = n(n+1)/2.
  2. Step 2: Compute for n = 10

    (10 × 11) ÷ 2 = 55.
  3. Final Answer:

    55 → Option B.
  4. Quick Check:

    1 + 2 + … + 10 = 55 ✅
Hint: Use n(n+1)/2 for natural numbers.
Common Mistakes: Forgetting to divide by 2.
4. Find the sum of the first 20 natural numbers.
medium
A. 200
B. 220
C. 230
D. 210

Solution

  1. Step 1: Recall the formula

    Sum of first n natural numbers = n(n+1)/2.
  2. Step 2: Compute for n = 20

    (20 × 21) ÷ 2 = 420 ÷ 2 = 210.
  3. Final Answer:

    210 → Option D.
  4. Quick Check:

    Pairing method: (1+20)=21, (2+19)=21, … 10 pairs × 21 = 210 ✅
Hint: n(n+1)/2 gives the exact sum; pairing terms gives a quick check.
Common Mistakes: Forgetting to divide by 2 or miscounting pairs.
5. Find the sum of the arithmetic series: 5 + 10 + 15 + … + 50.
medium
A. 250
B. 260
C. 275
D. 280

Solution

  1. Step 1: Identify the series

    First term a = 5, last term l = 50, common difference d = 5.
  2. Step 2: Count terms

    n = (l - a)/d + 1 = (50 - 5)/5 + 1 = 10.
  3. Step 3: Apply AP sum formula

    S = n/2 × (a + l) = 10/2 × (5 + 50) = 5 × 55 = 275.
  4. Final Answer:

    275 → Option C.
  5. Quick Check:

    Average term = (5 + 50)/2 = 27.5; 27.5 × 10 = 275 ✅
Hint: AP sum = average term × number of terms.
Common Mistakes: Forgetting to add +1 when counting terms.

Mock Test

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