Raised Fist0

Finding Principal (P)

Start learning this pattern below

Jump into concepts and practice - no test required

or
Recommended
Test this pattern10 questions across easy, medium, and hard to know if this pattern is strong

Introduction

Many simple interest problems give the interest earned (SI), the rate (R), and the time (T), and ask for the original sum - the principal (P). Knowing how to reverse the SI formula is essential for loan, investment, and backward-calculation problems.

Pattern: Finding Principal (P)

Pattern: Finding Principal (P)

Key concept: Rearrange SI = (P × R × T) / 100 to solve for P.

Formula:
P = (SI × 100) / (R × T)

Step-by-Step Example

Question

The simple interest earned on a sum for 3 years at 6% per annum is ₹540. Find the principal.

Options:
A. ₹2,500
B. ₹3,000
C. ₹3,500
D. ₹4,000

Solution

  1. Step 1: Identify the given values

    SI = 540, R = 6%, T = 3 years.
  2. Step 2: Write the rearranged formula

    P = (SI × 100) / (R × T)
  3. Step 3: Substitute values

    P = (540 × 100) / (6 × 3)
  4. Step 4: Simplify numerator and denominator

    Denominator = 6 × 3 = 18
    Numerator = 540 × 100 = 54,000
  5. Step 5: Divide to get the principal

    P = 54,000 ÷ 18 = 3,000
  6. Final Answer:

    ₹3,000 → Option B
  7. Quick Check:

    Yearly SI = (3,000 × 6)/100 = 180; for 3 years → 180 × 3 = 540 ✅

Quick Variations

1. SI given for fractional time (e.g., 2.5 years) - use T as decimal in formula.

2. SI given for months - convert months to years before substituting (e.g., 9 months = 0.75 year).

3. SI for multiple rates/time segments - compute total SI, then use overall R×T equivalent if applicable or split into parts and sum.

Trick to Always Use

  • Step 1 → Always convert time to years (months → divide by 12).
  • Step 2 → Rearrange formula clearly: P = (SI × 100) / (R × T).
  • Step 3 → Simplify numerator and denominator stepwise before final division to avoid arithmetic errors.

Summary

  • Use P = (SI × 100) / (R × T) to find the principal when SI, rate, and time are known.
  • Ensure rate is in percent and time is converted to years.
  • Always verify by recalculating SI using the found principal.
  • Simplify numerator and denominator before division to avoid mistakes.

Example to remember:
SI = ₹540 at 6% for 3 years → Principal = ₹3,000.

Practice

(1/5)
1. The simple interest earned on a sum for 3 years at 6% per annum is ₹540. Find the principal.
easy
A. 3000
B. 2500
C. 3500
D. 4000

Solution

  1. Step 1: Write the given values

    SI = 540, R = 6%, T = 3 years.
  2. Step 2: Apply the rearranged formula

    P = (SI × 100) / (R × T).
  3. Step 3: Substitute and simplify

    P = (540 × 100) / (6 × 3) = 54000 / 18 = 3000.
  4. Final Answer:

    ₹3000 → Option A
  5. Quick Check:

    Yearly SI = (3000 × 6)/100 = 180; ×3 = 540 ✅
Hint: Rearrange: P = (SI×100)/(R×T).
Common Mistakes: Forgetting to multiply R and T in the denominator or misplacing a zero.
2. A sum yields a simple interest of ₹375 at 5% per annum for 2 years. What is the principal?
easy
A. 3750
B. 3500
C. 4000
D. 3000

Solution

  1. Step 1: Note the given values

    SI = 375, R = 5%, T = 2 years.
  2. Step 2: Use the formula

    P = (SI × 100) / (R × T).
  3. Step 3: Substitute correctly

    P = (375 × 100) / (5 × 2) = 37500 / 10 = 3750.
  4. Final Answer:

    ₹3750 → Option A
  5. Quick Check:

    Yearly SI = (3750 × 5)/100 = 187.5; ×2 = 375 ✅
Hint: Compute (SI×100) first, then divide by (R×T).
Common Mistakes: Treating percentage 5% as 0.5 or forgetting decimal SI in quick check.
3. The simple interest on a certain sum for 2 years at 4.5% per annum is ₹225. Find the principal.
easy
A. 2400
B. 2500
C. 2600
D. 2250

Solution

  1. Step 1: Write SI, R, and T

    SI = 225, R = 4.5%, T = 2 years.
  2. Step 2: Apply formula carefully

    P = (225 × 100) / (4.5 × 2) = 22500 / 9.
  3. Step 3: Divide to find P

    P = 2500.
  4. Final Answer:

    ₹2500 → Option B
  5. Quick Check:

    Yearly SI = (2500 × 4.5)/100 = 112.5; ×2 = 225 ✅
Hint: When R is decimal (4.5), multiply R×T carefully (4.5×2=9).
Common Mistakes: Treating 4.5 as 45 or forgetting to convert months/years.
4. The simple interest on a sum of money for 4 years at 7% per annum amounts to ₹840. Find the principal.
medium
A. 2800
B. 3200
C. 3000
D. 3500

Solution

  1. Step 1: Identify the values

    SI = 840, R = 7%, T = 4 years.
  2. Step 2: Apply formula

    P = (840 × 100) / (7 × 4) = 84000 / 28.
  3. Step 3: Compute the division

    P = 3000.
  4. Final Answer:

    ₹3000 → Option C
  5. Quick Check:

    Yearly SI = (3000 × 7)/100 = 210; ×4 = 840 ✅
Hint: Multiply R and T first to get denominator (7×4=28).
Common Mistakes: Dividing by 4 then by 7 separately causing rounding errors.
5. A borrower paid simple interest of ₹612 on a loan for 2 years at 6% per annum. What was the principal borrowed?
medium
A. 5000
B. 5200
C. 4900
D. 5100

Solution

  1. Step 1: Note SI, R, and T

    SI = 612, R = 6%, T = 2 years.
  2. Step 2: Apply formula

    P = (612 × 100) / (6 × 2) = 61200 / 12.
  3. Step 3: Compute P

    P = 5100.
  4. Final Answer:

    ₹5100 → Option D
  5. Quick Check:

    Yearly SI = (5100 × 6)/100 = 306; ×2 = 612 ✅
Hint: Compute (R×T) first to simplify denominator.
Common Mistakes: Using incorrect denominator (e.g., 6×12 instead of 6×2) or misplacing zeros.