Introduction
In aptitude tests, many questions involve marks and exams. These problems are based on percentage of marks obtained, total marks, and passing marks.
Such questions are very practical because they reflect real exam scoring. By applying simple percentage formulas, we can solve them step by step.
Pattern: Marks & Exams
Pattern
The key idea: Marks obtained = (Percentage ÷ 100) × Total marks
To find pass marks, add/subtract the difference from the marks obtained as per the question.
Fail/Pass difference questions are solved by using total marks × (pass% ÷ 100).
Step-by-Step Example
Question
A student scores 40% of the total marks in an exam and fails by 20 marks. If the pass percentage is 50%, find the total marks of the exam.
Solution
-
Step 1: Represent total marks with a variable
Let total marks = M. -
Step 2: Calculate student's obtained marks
Marks obtained = (40/100) × M = 0.4M -
Step 3: Calculate pass marks
Pass marks = (50/100) × M = 0.5M -
Step 4: Apply failure condition
Pass marks - Obtained marks = 20 → 0.5M - 0.4M = 20 -
Step 5: Solve the equation
0.1M = 20 → M = 20 ÷ 0.1 = 200 -
Final Answer:
200 -
Quick Check:
Student’s marks = 40% of 200 = 80
Pass marks = 50% of 200 = 100
Difference = 20 ✅
Quick Variations
Sometimes the question gives marks scored and pass marks, and asks for the percentage. Use: (Marks scored ÷ Total marks) × 100.
If the student passes by X marks, then (Marks scored - Pass marks = X).
Trick to Always Use
- Step 1: Let total marks = M.
- Step 2: Write student’s score using %.
- Step 3: Write pass marks using %.
- Step 4: Apply pass/fail condition.
- Step 5: Solve and verify.
Summary
Summary
- Use Marks = (Percentage ÷ 100) × Total marks.
- Pass marks = (Pass% ÷ 100) × Total marks.
- Fail condition → Pass marks - Obtained = difference.
- Pass condition → Obtained - Pass marks = difference.
Example to remember:
Total marks = 200 when 40% fails by 20 marks and pass% = 50%
