0
0

Nature of Roots (Discriminant Method)

Introduction

The discriminant method helps determine the nature of the roots of a quadratic equation without solving it completely. It tells us whether the roots are real or imaginary and whether they are distinct or equal.

This method is important because it saves time and gives insight into the equation's behavior before finding the actual roots.

Pattern: Nature of Roots (Discriminant Method)

Pattern

The key idea is to calculate the discriminant: D = b² - 4ac.

Based on the value of D:

  • If D > 0 → Roots are real and distinct.
  • If D = 0 → Roots are real and equal.
  • If D < 0 → Roots are imaginary (complex conjugates).

Step-by-Step Example

Question

Find the nature of roots of the equation 2x² - 3x + 1 = 0.

Solution

  1. Step 1: Identify coefficients

    a = 2, b = -3, c = 1.

  2. Step 2: Calculate the discriminant

    D = b² - 4ac = (-3)² - 4(2)(1) = 9 - 8 = 1.

  3. Step 3: Interpret the result

    D > 0 ⇒ Roots are real and distinct.

  4. Final Answer:

    The roots are real and distinct.

  5. Quick Check:

    Solving the quadratic gives x = 1 and 0.5 → two distinct real roots ✅

Quick Variations

1. You can also be asked to find the range of values of a constant k for which the roots are real.

2. Sometimes the question asks for whether roots are equal or unequal.

3. Can also appear in problems involving word equations like motion or area-related problems.

Trick to Always Use

  • Step 1: Write down coefficients (a, b, c) clearly.
  • Step 2: Compute D = b² - 4ac.
  • Step 3: Compare D to 0 and decide the nature.
  • Step 4: Remember: D > 0 → distinct, D = 0 → equal, D < 0 → imaginary.

Summary

Summary

In the Discriminant Method:

  • The discriminant formula D = b² - 4ac is the key.
  • The sign of D directly tells the nature of the roots.
  • No need to solve the full equation - just compute D to classify roots.

Practice

(1/5)
1. Find the nature of the roots of the equation x² + 5x + 6 = 0.
easy
A. Real and distinct
B. Real and equal
C. Imaginary
D. None of these

Solution

  1. Step 1: Identify coefficients

    a = 1, b = 5, c = 6.

  2. Step 2: Compute discriminant

    D = b² - 4ac = 25 - 24 = 1.

  3. Step 3: Interpret

    Since D > 0, the roots are real and distinct.

  4. Final Answer:

    Real and distinct → Option A.

  5. Quick Check:

    Factors: (x + 2)(x + 3) ⇒ roots -2 and -3 (two distinct reals) ✅

Hint: If D > 0 → real and distinct.
Common Mistakes: Forgetting to compute 4ac or mis-evaluating b².
2. Determine the nature of roots of 2x² + 4x + 2 = 0.
easy
A. Real and equal
B. Real and distinct
C. Imaginary
D. Cannot be determined

Solution

  1. Step 1: Identify coefficients

    a = 2, b = 4, c = 2.

  2. Step 2: Compute discriminant

    D = b² - 4ac = 16 - 16 = 0.

  3. Step 3: Interpret

    Since D = 0, the equation has real and equal (repeated) roots.

  4. Final Answer:

    Real and equal → Option A.

  5. Quick Check:

    2x² +4x +2 = 2(x + 1)² ⇒ root x = -1 (double root) ✅

Hint: If D = 0 → one repeated real root (perfect square trinomial).
Common Mistakes: Failing to divide common factor before recognizing perfect square.
3. For the equation x² + 4x + 8 = 0, find the nature of its roots.
easy
A. Real and distinct
B. Imaginary
C. Real and equal
D. Cannot say

Solution

  1. Step 1: Identify coefficients

    a = 1, b = 4, c = 8.

  2. Step 2: Compute discriminant

    D = b² - 4ac = 16 - 32 = -16.

  3. Step 3: Interpret

    Since D < 0, the roots are imaginary (complex conjugates).

  4. Final Answer:

    Imaginary → Option B.

  5. Quick Check:

    Roots = -2 ± 2i (complex) - no real solutions ✅

Hint: If D < 0 → complex conjugate roots.
Common Mistakes: Forgetting the sign when subtracting 4ac from b².
4. Find the nature of roots for 3x² - 6x + 3 = 0.
medium
A. Real and distinct
B. Imaginary
C. Real and equal
D. None of these

Solution

  1. Step 1: Identify coefficients

    a = 3, b = -6, c = 3.

  2. Step 2: Compute discriminant

    D = b² - 4ac = 36 - 36 = 0.

  3. Step 3: Interpret

    Since D = 0, the roots are real and equal (repeated root).

  4. Final Answer:

    Real and equal → Option C.

  5. Quick Check:

    3x² -6x +3 = 3(x -1)² ⇒ root x = 1 (double) ✅

Hint: D = 0 indicates a repeated real root (perfect square).
Common Mistakes: Missing the factor 3 and not recognizing the perfect square form.
5. For the equation 5x² + 2x + 3 = 0, determine the nature of roots.
medium
A. Real and distinct
B. Real and equal
C. None
D. Imaginary

Solution

  1. Step 1: Identify coefficients

    a = 5, b = 2, c = 3.

  2. Step 2: Compute discriminant

    D = b² - 4ac = 4 - 60 = -56.

  3. Step 3: Interpret

    Since D < 0, the roots are imaginary (complex conjugates).

  4. Final Answer:

    Imaginary → Option D.

  5. Quick Check:

    Negative discriminant confirms no real roots (complex roots) ✅

Hint: Negative discriminant → complex roots; no real solutions.
Common Mistakes: Arithmetic error computing 4ac or forgetting to square b.

Mock Test

Ready for a challenge?

Take a 10-minute AI-powered test with 10 questions (Easy-Medium-Hard mix) and get instant SWOT analysis of your performance!

10 Questions
5 Minutes