Introduction
A very common type of average problem in aptitude exams involves consecutive numbers - natural numbers, even numbers, or odd numbers. These problems are simple once you know the property that the average of consecutive numbers is equal to their middle term.
This property helps you solve such problems quickly without adding all numbers.
Pattern: Average of Consecutive Numbers
Pattern
The average of consecutive numbers (whether natural, even, or odd) is always the middle number.
- If there are an odd count of numbers → Average = Middle number.
- If there are an even count of numbers → Average = Mean of the two middle numbers.
For a sequence of consecutive natural numbers from 1 to n: Average = (n + 1) ÷ 2.
For consecutive even or odd numbers: Average = (First + Last) ÷ 2.
Step-by-Step Example
Question
Find the average of the first 10 natural numbers.
Options:
- A. 5.5
- B. 6
- C. 4.5
- D. 5
Solution
-
Step 1: Understand the sequence
First 10 natural numbers = 1, 2, 3, …, 10. -
Step 2: Apply the formula
Average of first n natural numbers = (n + 1) ÷ 2. -
Step 3: Substitute the value of n
Average = (10 + 1) ÷ 2 = 11 ÷ 2 = 5.5. -
Final Answer:
5.5 → Option A -
Quick Check:
Middle numbers are 5 and 6 → (5 + 6) ÷ 2 = 5.5 ✅
Quick Variations
- Average of first 20 natural numbers = (20 + 1)/2 = 10.5.
- Average of consecutive even numbers from 2 to 20 = (2 + 20)/2 = 11.
- Average of consecutive odd numbers from 1 to 19 = (1 + 19)/2 = 10.
Trick to Always Use
- Average of consecutive numbers = middle term.
- If count is even → take mean of two middle terms.
- For first n natural numbers → formula (n + 1)/2.
- Shortcut saves time compared to adding all numbers.
Summary
Summary
The Average of Consecutive Numbers is solved using the middle number property or formula.
- Odd count: Average = Middle number.
- Even count: Average = Mean of two middle numbers.
- 1 to n: Average = (n + 1)/2.
- Consecutive even/odd numbers: Average = (First + Last)/2.
