Practice
Solution
Step 1: Locate INNER JOIN query in dictionary
The dictionary key 'INNER JOIN' maps to "SELECT A.id, A.name, B.city FROM A INNER JOIN B ON A.id = B.id;"Step 2: Confirm printed output format
The code prints "-- INNER JOIN --" followed by the query string exactly as stored.Final Answer:
Option C -> Option CQuick Check:
-- INNER JOIN -- SELECT A.id, A.name, B.city FROM A INNER JOIN B ON A.id = B.id; matches printed lines exactly [OK]
- Mixing LEFT JOIN query with INNER JOIN label
- Confusing SELF JOIN query with INNER JOIN
Solution
Step 1: Understand Serializable Guarantees
Serializable prevents all anomalies including dirty, non-repeatable, and phantom reads.Step 2: Analyze Performance Impact
To guarantee serializability, databases use strict locking or multi-version concurrency control with conflict detection, which can cause contention and reduce throughput.Step 3: Evaluate Other Options
Serializable allows dirty reads, which can corrupt data is false because Serializable prevents dirty reads. Serializable does not prevent phantom reads, so anomalies still occur is false because Serializable prevents phantom reads. Serializable is the default isolation level in most databases, so it offers no advantage is false; default levels vary.Final Answer:
Option A -> Option AQuick Check:
Serializable trades off performance for correctness, which can be costly in high-throughput systems.
- Believing Serializable allows dirty reads
- Thinking phantom reads occur at Serializable
- Assuming Serializable is default everywhere
Solution
Step 1: Evaluate read scalability
Replication allows distributing reads to replicas, improving read throughput.Step 2: Assess consistency guarantees
Most replication setups, especially asynchronous, do not guarantee strong consistency at all times; replicas can lag behind.Step 3: Consider fault tolerance
Replication enables failover to replicas, improving availability.Step 4: Understand replication latency
There is inherent latency between primary and replicas, causing potential stale reads.Final Answer:
Option C -> Option CQuick Check:
Replication usually provides eventual, not strong, consistency.
- Assuming replication always ensures strong consistency
- Ignoring replication lag effects
- Confusing replication with distributed transactions
Solution
Step 1: Analyze the execute method calls
Each node calls execute on its next node exactly once, forming a simple chain of n calls.Step 2: Determine total calls and complexity
Since each node executes once, total time is proportional to n, so O(n).Final Answer:
Option C -> Option CQuick Check:
Each clause processed once, no repeated work [OK]
- Thinking recursion causes O(n^2) due to nested calls
LIMIT is applied without an ORDER BY clause. Which of the following statements about the behavior of LIMIT in this case is correct, and what adjustment should be made to the simulation to reflect real SQL behavior?Solution
Step 1: Understand LIMIT behavior without ORDER BY
Without ORDER BY, LIMIT returns an arbitrary subset of rows, not sorted, so results may be inconsistent.Step 2: Adjust simulation to reflect logical execution
Simulation should keep LIMIT as the last clause executed but clarify it does not guarantee sorted output without ORDER BY.Final Answer:
Option D -> Option DQuick Check:
LIMIT applies last but unordered without ORDER BY [OK]
- Assuming LIMIT sorts rows by default
