The Z-transform helps us study signals and systems by turning sequences into simpler formulas. Knowing common pairs makes solving problems faster and easier.
Common Z-transform pairs in Signal Processing
Z{f[n]} = F(z) = \sum_{n=0}^{\infty} f[n] z^{-n}This formula means: the Z-transform of a sequence f[n] is a sum of terms f[n] times z to the power of -n.
Here, z is a complex number variable, and n is the index of the sequence starting at 0.
Z{1} = 1 / (1 - z^{-1}), |z| > 1Z{a^n} = 1 / (1 - a z^{-1}), |z| > |a|Z{n} = z^{-1} / (1 - z^{-1})^2, |z| > 1Z{u[n]} = 1 / (1 - z^{-1}), |z| > 1This code uses SymPy to calculate the Z-transform of three common sequences: constant 1, geometric a^n, and linear n. It sums the terms and simplifies the results to show the common Z-transform pairs.
import sympy as sp z, a = sp.symbols('z a', complex=True) n = sp.symbols('n', integer=True, nonnegative=True) # Define sequences constant_seq = 1 geom_seq = a**n linear_seq = n # Define Z-transform variable Z = lambda f: sp.summation(f * z**(-n), (n, 0, sp.oo)) # Calculate Z-transforms Z_constant = Z(constant_seq) Z_geom = Z(geom_seq) Z_linear = Z(linear_seq) # Simplify results Z_constant_simplified = sp.simplify(Z_constant) Z_geom_simplified = sp.simplify(Z_geom) Z_linear_simplified = sp.simplify(Z_linear) print(f"Z-transform of constant sequence 1: {Z_constant_simplified}") print(f"Z-transform of geometric sequence a^n: {Z_geom_simplified}") print(f"Z-transform of linear sequence n: {Z_linear_simplified}")
The Z-transform is usually defined for n starting at 0, which fits many digital signal cases.
The region of convergence (ROC) is important to know where the Z-transform formula works.
Common pairs help avoid doing the sum every time and speed up analysis.
The Z-transform changes sequences into algebraic expressions.
Common pairs include constant, geometric, and linear sequences.
Knowing these pairs helps analyze digital signals and systems easily.
Practice
x[n] = a^n u[n], where u[n] is the unit step?Solution
Step 1: Recall the definition of the Z-transform for geometric sequences
The Z-transform ofa^n u[n]is a standard pair given by the sum of a geometric series: \( \sum_{n=0}^\infty a^n z^{-n} = \frac{1}{1 - a z^{-1}} \) for \( |z| > |a| \).Step 2: Match the formula with the options
X(z) = 1 / (1 - a z^{-1}), |z| > |a| matches the formula exactly with the correct region of convergence.Final Answer:
X(z) = 1 / (1 - a z^{-1}), |z| > |a| -> Option BQuick Check:
Geometric sequence Z-transform = 1/(1 - a z^{-1}) [OK]
- Confusing region of convergence
- Mixing numerator and denominator terms
- Using wrong inequality for |z|
δ[n]?Solution
Step 1: Understand the unit impulse sequence
The unit impulseδ[n]is 1 at n=0 and 0 elsewhere.Step 2: Calculate the Z-transform
By definition, \( X(z) = \sum_{n=-\infty}^\infty δ[n] z^{-n} = z^{0} = 1 \).Final Answer:
X(z) = 1 -> Option DQuick Check:
Impulse Z-transform = 1 [OK]
- Confusing impulse with step function
- Adding z terms unnecessarily
- Forgetting impulse is zero except at n=0
x[n] = n u[n]?Solution
Step 1: Recall the Z-transform of the sequence n u[n]
The sequencen u[n]has Z-transform \( X(z) = \frac{z^{-1}}{(1 - z^{-1})^2} \) with region of convergence \( |z| > 1 \).Step 2: Match the formula with the options
X(z) = z^{-1} / (1 - z^{-1})^2, |z| > 1 matches the formula exactly including the region of convergence.Final Answer:
X(z) = z^{-1} / (1 - z^{-1})^2, |z| > 1 -> Option AQuick Check:
Linear sequence Z-transform = z^{-1}/(1 - z^{-1})^2 [OK]
- Confusing powers of z
- Using (z - 1) instead of (1 - z^{-1})
- Ignoring region of convergence
x[n] = a^n u[n]: X(z) = 1 / (1 - z a^{-1})Solution
Step 1: Recall the correct Z-transform formula for a^n u[n]
The correct formula is \( X(z) = \frac{1}{1 - a z^{-1}} \), not \( 1/(1 - z a^{-1}) \).Step 2: Analyze the given expression
The given expression swaps z and a in the denominator, which changes the meaning and is incorrect.Final Answer:
The variable z and a are swapped in the denominator -> Option AQuick Check:
Correct formula uses a z^{-1}, not z a^{-1} [OK]
- Swapping z and a in denominator
- Ignoring negative powers of z
- Missing region of convergence
x[n] = (1/2)^n u[n] + 3 δ[n], what is the combined Z-transform X(z)?Solution
Step 1: Find Z-transform of each sequence part
The Z-transform of(1/2)^n u[n]is \( \frac{1}{1 - (1/2) z^{-1}} \) with \( |z| > 1/2 \). The Z-transform of3 δ[n]is 3.Step 2: Add the transforms for combined sequence
Since Z-transform is linear, add both: \( X(z) = 3 + \frac{1}{1 - (1/2) z^{-1}} \).Final Answer:
X(z) = 3 + 1 / (1 - (1/2) z^{-1}), |z| > 1/2 -> Option CQuick Check:
Sum of transforms = 3 + 1/(1 - 0.5 z^{-1}) [OK]
- Multiplying instead of adding transforms
- Incorrect region of convergence
- Wrong coefficient placement
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