Common Z-transform pairs in Signal Processing - Time & Space Complexity
We want to understand how the time to find Z-transform pairs grows as the input size increases.
How does the number of operations change when we use common Z-transform pairs for longer sequences?
Analyze the time complexity of the following code snippet.
// Example: Compute Z-transform of a finite sequence using common pairs
function zTransform(sequence, z) {
let result = 0;
for (let n = 0; n < sequence.length; n++) {
result += sequence[n] * Math.pow(z, -n);
}
return result;
}
This code calculates the Z-transform by summing terms of the input sequence multiplied by powers of z.
- Primary operation: Loop over each element of the input sequence.
- How many times: Once for each element in the sequence (n times).
As the sequence length grows, the number of operations grows linearly.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | 10 additions and multiplications |
| 100 | 100 additions and multiplications |
| 1000 | 1000 additions and multiplications |
Pattern observation: Doubling the input size roughly doubles the work needed.
Time Complexity: O(n)
This means the time to compute the Z-transform grows directly with the length of the input sequence.
[X] Wrong: "Using common Z-transform pairs makes the computation instant regardless of input size."
[OK] Correct: Even with known pairs, computing the transform for longer sequences still requires processing each element, so time grows with input length.
Understanding how computation time grows with input size helps you explain your approach clearly and shows you know how to handle larger data efficiently.
"What if we used a recursive formula to compute the Z-transform instead of a loop? How would the time complexity change?"
Practice
x[n] = a^n u[n], where u[n] is the unit step?Solution
Step 1: Recall the definition of the Z-transform for geometric sequences
The Z-transform ofa^n u[n]is a standard pair given by the sum of a geometric series: \( \sum_{n=0}^\infty a^n z^{-n} = \frac{1}{1 - a z^{-1}} \) for \( |z| > |a| \).Step 2: Match the formula with the options
X(z) = 1 / (1 - a z^{-1}), |z| > |a| matches the formula exactly with the correct region of convergence.Final Answer:
X(z) = 1 / (1 - a z^{-1}), |z| > |a| -> Option BQuick Check:
Geometric sequence Z-transform = 1/(1 - a z^{-1}) [OK]
- Confusing region of convergence
- Mixing numerator and denominator terms
- Using wrong inequality for |z|
δ[n]?Solution
Step 1: Understand the unit impulse sequence
The unit impulseδ[n]is 1 at n=0 and 0 elsewhere.Step 2: Calculate the Z-transform
By definition, \( X(z) = \sum_{n=-\infty}^\infty δ[n] z^{-n} = z^{0} = 1 \).Final Answer:
X(z) = 1 -> Option DQuick Check:
Impulse Z-transform = 1 [OK]
- Confusing impulse with step function
- Adding z terms unnecessarily
- Forgetting impulse is zero except at n=0
x[n] = n u[n]?Solution
Step 1: Recall the Z-transform of the sequence n u[n]
The sequencen u[n]has Z-transform \( X(z) = \frac{z^{-1}}{(1 - z^{-1})^2} \) with region of convergence \( |z| > 1 \).Step 2: Match the formula with the options
X(z) = z^{-1} / (1 - z^{-1})^2, |z| > 1 matches the formula exactly including the region of convergence.Final Answer:
X(z) = z^{-1} / (1 - z^{-1})^2, |z| > 1 -> Option AQuick Check:
Linear sequence Z-transform = z^{-1}/(1 - z^{-1})^2 [OK]
- Confusing powers of z
- Using (z - 1) instead of (1 - z^{-1})
- Ignoring region of convergence
x[n] = a^n u[n]: X(z) = 1 / (1 - z a^{-1})Solution
Step 1: Recall the correct Z-transform formula for a^n u[n]
The correct formula is \( X(z) = \frac{1}{1 - a z^{-1}} \), not \( 1/(1 - z a^{-1}) \).Step 2: Analyze the given expression
The given expression swaps z and a in the denominator, which changes the meaning and is incorrect.Final Answer:
The variable z and a are swapped in the denominator -> Option AQuick Check:
Correct formula uses a z^{-1}, not z a^{-1} [OK]
- Swapping z and a in denominator
- Ignoring negative powers of z
- Missing region of convergence
x[n] = (1/2)^n u[n] + 3 δ[n], what is the combined Z-transform X(z)?Solution
Step 1: Find Z-transform of each sequence part
The Z-transform of(1/2)^n u[n]is \( \frac{1}{1 - (1/2) z^{-1}} \) with \( |z| > 1/2 \). The Z-transform of3 δ[n]is 3.Step 2: Add the transforms for combined sequence
Since Z-transform is linear, add both: \( X(z) = 3 + \frac{1}{1 - (1/2) z^{-1}} \).Final Answer:
X(z) = 3 + 1 / (1 - (1/2) z^{-1}), |z| > 1/2 -> Option CQuick Check:
Sum of transforms = 3 + 1/(1 - 0.5 z^{-1}) [OK]
- Multiplying instead of adding transforms
- Incorrect region of convergence
- Wrong coefficient placement
Ready to prove it?
Pass the test and this pattern moves unknown
