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Signal Processingdata~10 mins

Fast Fourier Transform (FFT) algorithm in Signal Processing - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to import the FFT function from the numpy library.

Signal Processing
from numpy.fft import [1]
Drag options to blanks, or click blank then click option'
Aifft
Brfft
Cfftshift
Dfft
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'ifft' which computes the inverse FFT instead.
Using 'fftshift' which shifts zero frequency component.
Using 'rfft' which computes FFT for real inputs only.
2fill in blank
medium

Complete the code to compute the FFT of the signal stored in variable 'signal'.

Signal Processing
spectrum = [1](signal)
Drag options to blanks, or click blank then click option'
Anp.fft.fft
Bnp.fft.ifft
Cnp.fft.rfft
Dnp.fft.fftshift
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'ifft' which computes inverse FFT.
Using 'fftshift' which rearranges FFT output.
Using 'rfft' which is for real-valued inputs only.
3fill in blank
hard

Fix the error in the code to correctly compute the magnitude spectrum from FFT output.

Signal Processing
magnitude = [1](spectrum)
Drag options to blanks, or click blank then click option'
Anp.abs
Bnp.real
Cnp.angle
Dnp.imag
Attempts:
3 left
💡 Hint
Common Mistakes
Using np.angle which gives phase, not magnitude.
Using np.real which only gives real part.
Using np.imag which gives imaginary part.
4fill in blank
hard

Fill both blanks to create a frequency array matching the FFT output length.

Signal Processing
freqs = np.fft.[1](len(signal)) * [2]
Drag options to blanks, or click blank then click option'
Afftfreq
Bfftshift
Csampling_rate
Dnp.pi
Attempts:
3 left
💡 Hint
Common Mistakes
Using fftshift instead of fftfreq for frequency bins.
Multiplying by np.pi instead of sampling rate.
Not multiplying frequency bins by sampling rate.
5fill in blank
hard

Fill all three blanks to compute the inverse FFT and retrieve the original signal.

Signal Processing
recovered_signal = np.fft.[1]( [2] )
real_signal = np.[3](recovered_signal)
Drag options to blanks, or click blank then click option'
Aifft
Bspectrum
Creal
Dabs
Attempts:
3 left
💡 Hint
Common Mistakes
Using fft instead of ifft for inverse transform.
Using abs instead of real to get original signal.
Passing wrong variable to ifft.

Practice

(1/5)
1. What is the main purpose of the Fast Fourier Transform (FFT) algorithm in signal processing?
easy
A. To compress the signal data for storage
B. To convert a signal from time domain to frequency domain
C. To filter out noise from the signal
D. To increase the amplitude of the signal

Solution

  1. Step 1: Understand FFT role and compare options

    FFT transforms time-domain signal to frequency domain. A matches exactly; B is compression, C filtering, D amplification.
  2. Final Answer:

    To convert a signal from time domain to frequency domain -> Option B
  3. Quick Check:

    FFT = Time to Frequency conversion [OK]
Hint: FFT changes signal view from time to frequency fast [OK]
Common Mistakes:
  • Confusing FFT with noise filtering
  • Thinking FFT compresses data
  • Assuming FFT amplifies signals
2. Which of the following is the correct way to import the FFT function from NumPy in Python?
easy
A. from numpy import fft
B. import numpy.fft as fft
C. import fft from numpy
D. from numpy.fft import fft

Solution

  1. Step 1: Recall and match Python import syntax

    Correct for specific function: 'from numpy.fft import fft' (C). A imports submodule, B aliases submodule (requires fft.fft()), D invalid.
  2. Final Answer:

    from numpy.fft import fft -> Option D
  3. Quick Check:

    Correct import syntax = from numpy.fft import fft [OK]
Hint: Use 'from module import function' to import FFT [OK]
Common Mistakes:
  • Using 'import fft from numpy' which is invalid syntax
  • Importing whole numpy.fft as fft causing confusion
  • Trying 'from numpy import fft' which imports the module, not function
3. Given the Python code:
import numpy as np
signal = np.array([1, 0, -1, 0])
fft_result = np.fft.fft(signal)
print(np.round(fft_result, 2))

What is the output?
medium
A. [0.+0.j 0.+2.j 0.+0.j 0.-2.j]
B. [0.+0.j 0.+0.j 0.+0.j 0.+0.j]
C. [0.+0.j 2.+0.j 0.+0.j 2.+0.j]
D. [0.+0.j 1.+0.j 0.+0.j 1.+0.j]

Solution

  1. Step 1: Compute and verify FFT output

    np.fft.fft([1,0,-1,0]) corresponds to a sine wave component, resulting in imaginary parts at k=1 and k=3. The output is [0.+0.j 0.+2.j 0.+0.j 0.-2.j], matching [0.+0.j 0.+2.j 0.+0.j 0.-2.j].
  2. Final Answer:

    [0.+0.j 0.+2.j 0.+0.j 0.-2.j] -> Option A
  3. Quick Check:

    FFT sine wave = imaginary components at k=1,3 [OK]
Hint: Sine-like signals yield imaginary FFT components [OK]
Common Mistakes:
  • Confusing cosine signal with sine (imaginary output)
  • Confusing zeros with non-zero frequency components
  • Rounding incorrectly or not at all
4. Consider this Python code snippet:
import numpy as np
signal = [1, 2, 3, 4]
fft_result = fft(signal)
print(fft_result.real)

It raises an error. What is the most likely cause?
medium
A. signal should be a NumPy array, not a list
B. np.fft.fft does not have a real attribute
C. Missing import statement for fft
D. print statement syntax is incorrect

Solution

  1. Step 1: Trace code execution for error

    fft(signal) raises NameError: 'fft' undefined. Import is numpy as np (use np.fft.fft); no direct fft import (e.g., from numpy.fft import fft). A, B, D unrelated.
  2. Final Answer:

    Missing import statement for fft -> Option C
  3. Quick Check:

    Undefined fft = missing import [OK]
Hint: Import fft properly: from numpy.fft import fft [OK]
Common Mistakes:
  • Not importing the fft function when using fft()
  • Thinking .real is invalid on FFT output
  • Confusing print syntax errors
5. You have a noisy signal sampled at 1000 Hz stored in a NumPy array data. You want to remove frequencies above 100 Hz using FFT. Which approach correctly achieves this?
hard
A. Compute FFT, zero out components with frequency > 100 Hz, then inverse FFT
B. Compute FFT, keep only first 100 components, then inverse FFT
C. Apply FFT and multiply all values by 0.1 to reduce noise
D. Use FFT to find max frequency and subtract it from signal

Solution

  1. Step 1: Outline correct FFT low-pass filtering

    FFT to freq domain (use fftfreq for bins), zero coeffs where |freq| > 100 (fs=1000, cutoff index ~100/500=0.2*N), ifft back. Matches B precisely; A ignores freq mapping, C/D ineffective.
  2. Final Answer:

    Compute FFT, zero out components with frequency > 100 Hz, then inverse FFT -> Option A
  3. Quick Check:

    Zero high freq + ifft = low-pass filter [OK]
Hint: Zero unwanted FFT frequencies, then inverse transform [OK]
Common Mistakes:
  • Confusing component count with frequency
  • Scaling FFT values instead of zeroing
  • Misusing FFT to subtract frequencies directly
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10 questions~5 mineasy hard