Network redundancy (ring topology) in SCADA systems - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a ring topology with 4 nodes.

SCADA systems

ring_topology = ['Node1', 'Node2', 'Node3', [1]]

Drag options to blanks, or click blank then click option'

A'Node4'

B'Node6'

C'Node5'

D'Node7'

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing a node name that breaks the sequence.

The ring topology connects nodes in a closed loop. The fourth node should be 'Node4' to complete the ring.

2fill in blank

medium

Complete the code to add a link between the last and first node to form a ring.

SCADA systems

links = [('Node1', 'Node2'), ('Node2', 'Node3'), ('Node3', 'Node4'), [1]]

Drag options to blanks, or click blank then click option'

A('Node3', 'Node1')

B('Node4', 'Node2')

C('Node4', 'Node1')

D('Node1', 'Node3')

Attempts:

3 left

💡 Hint

Common Mistakes

Connecting nodes that do not close the ring.

In a ring topology, the last node connects back to the first node to close the loop.

3fill in blank

hard

Fix the error in the code to correctly check if the network is a ring.

SCADA systems

is_ring = (len(links) == len(nodes) and links[[1]] == ('Node4', 'Node1'))

Drag options to blanks, or click blank then click option'

A1

B-1

C0

D2

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 or 1 instead of -1 for the last element.

The last link in the list is at index -1, which should connect 'Node4' to 'Node1' to confirm the ring.

4fill in blank

hard

Fill both blanks to create a function that returns True if the network is a ring.

SCADA systems

def check_ring(nodes, links):
    return len(links) == len(nodes) and links[[1]] == (nodes[-1], [2])

Drag options to blanks, or click blank then click option'

A-1

Bnodes[0]

Cnodes[1]

Dnodes[-2]

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong indices for last link or first node.

The last link should be at index -1, connecting the last node to the first node (nodes[0]) to form a ring.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps each node to its next node in the ring.

SCADA systems

next_node = {nodes[[1]]: nodes[[2]] for [3] in range(len(nodes))}

Drag options to blanks, or click blank then click option'

Ai

B(i + 1) % len(nodes)

Dj

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong variable names or forgetting modulo for wrap-around.

We use 'i' as the current index, and '(i + 1) % len(nodes)' to get the next node index, wrapping around to form a ring.