Navigation and screen hierarchy in SCADA systems - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define the main screen in the SCADA system.

SCADA systems

main_screen = Screen(name=[1])

Drag options to blanks, or click blank then click option'

AmainScreen

BMainScreen

C'main_screen'

D"MainScreen"

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting to put quotes around the screen name

Using variable names without quotes

The screen name must be a string, so it needs to be enclosed in quotes.

2fill in blank

medium

Complete the code to add a child screen to the main screen.

SCADA systems

main_screen.add_child([1])

Drag options to blanks, or click blank then click option'

AchildScreen

B'childScreen'

Cchild_screen

D"ChildScreen"

Attempts:

3 left

💡 Hint

Common Mistakes

Passing the screen name as a string instead of the screen object

Using quotes around the variable name

The add_child method expects a Screen object, so the variable name without quotes is correct.

3fill in blank

hard

Fix the error in the code to navigate to a screen by its name.

SCADA systems

navigate_to_screen([1])

Drag options to blanks, or click blank then click option'

A"screen_name"

Bscreen_name

CscreenName

D'screenName'

Attempts:

3 left

💡 Hint

Common Mistakes

Passing variable names without quotes

Using single quotes instead of double quotes if the system requires double quotes

The function expects the screen name as a string, so it must be in quotes.

4fill in blank

hard

Fill both blanks to create a screen hierarchy with a parent and child screen.

SCADA systems

parent_screen = Screen(name=[1])
parent_screen.add_child([2])

Drag options to blanks, or click blank then click option'

A"ParentScreen"

Bchild_screen

C"ChildScreen"

DparentScreen

Attempts:

3 left

💡 Hint

Common Mistakes

Using variable names without quotes for screen names

Putting quotes around the child screen variable

The parent screen name must be a string, and the child screen is a variable passed without quotes.

5fill in blank

hard

Fill all three blanks to define a screen dictionary with screen names as keys and screen objects as values, filtering only active screens.

SCADA systems

active_screens = { [1]: [2] for [1] in screens if screens[[1]].[3] }

Drag options to blanks, or click blank then click option'

Ascreen_name

Bscreens[screen_name]

Cis_active

Dscreen

Attempts:

3 left

💡 Hint

Common Mistakes

Using inconsistent variable names for keys and values

Checking wrong attribute for active status

Use 'screen_name' as the key variable, 'screens[screen_name]' as the value, and check the 'is_active' attribute.