Communication network topology in SCADA systems - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a star topology where all nodes connect to a central hub.

SCADA systems

topology = {'hub': ['node1', 'node2', 'node3'], 'type': '[1]'}

Drag options to blanks, or click blank then click option'

Aring

Bmesh

Cstar

Dbus

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing 'ring' or 'bus' which connect nodes differently.

A star topology connects all nodes to a central hub.

2fill in blank

medium

Complete the code to add a new node to a mesh topology.

SCADA systems

mesh_nodes = ['node1', 'node2', 'node3']
mesh_nodes.[1]('node4')

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Aappend

Bremove

Cpop

Dclear

Attempts:

3 left

💡 Hint

Common Mistakes

Using remove() or pop() which delete elements.

Use append() to add a new node to the list.

3fill in blank

hard

Fix the error in the code to correctly check if a node is in a bus topology.

SCADA systems

bus_nodes = ['node1', 'node2', 'node3']
if 'node4' [1] bus_nodes:
    print('Node found')

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Anot in

Bin

Cis

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'is' or '==' which compare identity or equality, not membership.

Use 'in' to check membership in a list.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension mapping nodes to their connection count in a mesh.

SCADA systems

connections = {node: len([1]) for node in [2]

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Amesh_nodes

Cbus_nodes

Dstar_nodes

Attempts:

3 left

💡 Hint

Common Mistakes

Using different node lists causing wrong counts.

Each node connects to all nodes in mesh_nodes, so use mesh_nodes for both.

5fill in blank

hard

Fill all three blanks to filter nodes with more than 2 connections in the topology dictionary.

SCADA systems

filtered = {node: count for node, count in topology.[1]() if count [2] [3]

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Aitems

B>

C2

Dkeys

Attempts:

3 left

💡 Hint

Common Mistakes

Using keys() which returns only keys, not pairs.

Use items() to get node-count pairs, then filter counts greater than 2.