What will be the output when accessing the Raspberry Pi web server URL if the server code includes:

medium📝 Predict Output Q13 of 15

Raspberry Pi - Web Server and API

from http.server import SimpleHTTPRequestHandler
from socketserver import TCPServer

PORT = 8080

with TCPServer(("", PORT), SimpleHTTPRequestHandler) as httpd:
    print(f"Serving at port {PORT}")
    httpd.handle_request()

and a user visits http://raspberrypi.local:8080/?

AServer handles one request and then stops

BServer runs forever and serves multiple requests

CServing at port 8080

DSyntaxError due to missing parentheses

Step-by-Step Solution

Solution:

Step 1: Understand the use of handle_request()
The method handle_request() processes only one HTTP request and then stops.
Step 2: Analyze the code behavior on user access
When the user visits the URL, the server will serve that single request and then stop running.
Final Answer:
Server handles one request and then stops -> Option A
Quick Check:
handle_request() = single request served [OK]

Quick Trick: handle_request() serves one request only [OK]

Common Mistakes:

MISTAKES

Confusing handle_request() with serve_forever()
Expecting server to run continuously
Thinking print output is the server response

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What will be the output when accessing the Raspberry Pi web server URL if the server code includes:

Step 1: Understand the use of handle_request()

Step 2: Analyze the code behavior on user access

Final Answer:

Quick Check:

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