[Solved] What is wrong with this code snippet for sending an email alert?import smtplib sensor_value = 85 if sensor_value > 80: smtp = smtplib.SMTP('smtp.gmail.com', 587) smtp.... | Raspberry Pi

Raspberry Pi - Automation and Scheduling

What is wrong with this code snippet for sending an email alert?

import smtplib
sensor_value = 85
if sensor_value > 80:
    smtp = smtplib.SMTP('smtp.gmail.com', 587)
    smtp.sendmail(from_addr, to_addr, message)
    smtp.quit()

AIncorrect SMTP server address

BMissing starttls() call before sending email

CNo condition to check sensor value

Dsmtp.quit() should be called before sendmail()

Step-by-Step Solution

Solution:

Step 1: Review SMTP email sending steps
For Gmail SMTP on port 587, starttls() must be called to secure the connection before sending email.
Step 2: Check other parts
Server address is correct, condition exists, quit() is correctly after sendmail().
Final Answer:
Missing starttls() call before sending email -> Option B
Quick Check:
Use starttls() before sendmail() with Gmail SMTP [OK]

Quick Trick: Call starttls() before sending email via SMTP [OK]

Common Mistakes:

MISTAKES

Skipping starttls()
Wrong SMTP server
Calling quit() too early

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What is wrong with this code snippet for sending an email alert?

Step 1: Review SMTP email sending steps

Step 2: Check other parts

Final Answer:

Quick Check:

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