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Raspberry Piprogramming~30 mins

Serving sensor data as JSON API in Raspberry Pi - Mini Project: Build & Apply

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Serving sensor data as JSON API
📖 Scenario: You have a Raspberry Pi connected to a temperature sensor. You want to share the sensor readings over a simple web API that returns the data in JSON format. This way, other devices or apps can easily get the current temperature.
🎯 Goal: Build a small Python program that reads temperature data from a sensor (simulated), sets up a web server, and serves the sensor data as a JSON response when accessed.
📋 What You'll Learn
Create a dictionary with sensor data including 'temperature' and 'unit'.
Create a variable called 'port' to set the server port number.
Use Flask to create a web server with a route '/' that returns the sensor data as JSON.
Print a message showing the server is running on the specified port.
💡 Why This Matters
🌍 Real World
Sharing sensor data as JSON over a network is common in IoT projects, home automation, and remote monitoring.
💼 Career
Understanding how to serve JSON APIs is important for backend development, embedded systems, and working with connected devices.
Progress0 / 4 steps
1
Create sensor data dictionary
Create a dictionary called sensor_data with these exact entries: 'temperature': 23.5 and 'unit': 'Celsius'.
Raspberry Pi
Need a hint?

Use curly braces to create a dictionary with keys 'temperature' and 'unit'.

2
Set server port variable
Create a variable called port and set it to 5000.
Raspberry Pi
Need a hint?

Just assign the number 5000 to the variable named port.

3
Create Flask app and route
Import Flask and jsonify from flask. Create a Flask app called app. Define a route for '/' that returns jsonify(sensor_data).
Raspberry Pi
Need a hint?

Use @app.route('/') to create the route and return the sensor_data as JSON.

4
Run the Flask server and print message
Add the code to run the Flask app with app.run(host='0.0.0.0', port=port). Before running, print f"Server running on port {port}".
Raspberry Pi
Need a hint?

Use print(f"Server running on port {port}") and then app.run(host='0.0.0.0', port=port).