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Raspberry Piprogramming~5 mins

Multiple I2C devices on same bus in Raspberry Pi - Time & Space Complexity

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Time Complexity: Multiple I2C devices on same bus
O(n)
Understanding Time Complexity

When using multiple I2C devices on the same bus, it's important to understand how the communication time grows as you add more devices.

We want to know how the total time to communicate changes when the number of devices increases.

Scenario Under Consideration

Analyze the time complexity of the following code snippet.


import smbus

bus = smbus.SMBus(1)
addresses = [0x20, 0x21, 0x22]  # I2C device addresses

def read_all_devices():
    for addr in addresses:
        data = bus.read_byte(addr)
        print(f"Data from {hex(addr)}: {data}")

This code reads one byte from each I2C device on the bus and prints it.

Identify Repeating Operations
  • Primary operation: Loop over the list of device addresses to read data.
  • How many times: Once per device in the list.
How Execution Grows With Input

Each device adds one more read operation, so the total time grows directly with the number of devices.

Input Size (n)Approx. Operations
1010 reads
100100 reads
10001000 reads

Pattern observation: The time increases in a straight line as more devices are added.

Final Time Complexity

Time Complexity: O(n)

This means the time to read all devices grows directly in proportion to how many devices are on the bus.

Common Mistake

[X] Wrong: "Adding more devices won't affect total communication time much because I2C is fast."

[OK] Correct: Each device requires its own read operation, so total time adds up linearly with device count.

Interview Connect

Understanding how communication time grows with device count helps you design efficient sensor networks and troubleshoot delays in real projects.

Self-Check

"What if we read multiple bytes from each device instead of one? How would the time complexity change?"

Practice

(1/5)
1.

What is the main requirement to connect multiple I2C devices on the same bus?

Choose the best answer.

easy
A. Each device must have a unique I2C address.
B. Each device must use a different bus.
C. Devices must be connected with separate wires.
D. Devices must have the same address to communicate.

Solution

  1. Step 1: Understand I2C bus addressing

    I2C devices share the same two wires but must have unique addresses to avoid conflicts.
  2. Step 2: Identify the correct requirement

    Since devices share the bus, unique addresses allow the master to select each device individually.
  3. Final Answer:

    Each device must have a unique I2C address. -> Option A
  4. Quick Check:

    Unique addresses = multiple devices on one bus [OK]
Hint: Remember: unique addresses prevent device conflicts on I2C [OK]
Common Mistakes:
  • Thinking devices need separate wires
  • Assuming devices can share the same address
  • Believing each device needs its own bus
2.

Which Python code snippet correctly initializes communication with two I2C devices at addresses 0x20 and 0x21 on the same bus?

import smbus2
bus = smbus2.SMBus(1)

# What comes next?
easy
A. device1 = smbus2.SMBus(0x20) device2 = smbus2.SMBus(0x21)
B. device1 = bus.read_byte(0x20) device2 = bus.read_byte(0x21)
C. device1 = 0x20 device2 = 0x21
D. device1 = bus device2 = bus

Solution

  1. Step 1: Understand bus and device addressing

    The bus object is created once; devices are identified by their addresses.
  2. Step 2: Assign device addresses as variables

    Assigning device addresses to variables allows easy communication calls later.
  3. Final Answer:

    device1 = 0x20\ndevice2 = 0x21 -> Option C
  4. Quick Check:

    Bus once, devices by address [OK]
Hint: Create one bus object; use addresses to identify devices [OK]
Common Mistakes:
  • Trying to create multiple bus objects for each device
  • Calling read_byte immediately without setup
  • Assigning bus object directly to devices
3.

Given this Python code snippet on a Raspberry Pi with two I2C devices at addresses 0x20 and 0x21:

import smbus2
bus = smbus2.SMBus(1)

value1 = bus.read_byte(0x20)
value2 = bus.read_byte(0x21)
print(value1, value2)

What will be the output if device 0x20 returns 10 and device 0x21 returns 20?

medium
A. 10 20
B. 20 10
C. 0 0
D. Error: Address not found

Solution

  1. Step 1: Read bytes from each device address

    The code reads one byte from address 0x20 and one from 0x21.
  2. Step 2: Print the values in order

    Since value1 reads from 0x20 (returns 10) and value2 from 0x21 (returns 20), print outputs "10 20".
  3. Final Answer:

    10 20 -> Option A
  4. Quick Check:

    Read from 0x20 then 0x21 = 10 20 [OK]
Hint: Read bytes by address order matches output order [OK]
Common Mistakes:
  • Mixing up device addresses and values
  • Assuming output is reversed
  • Expecting error without checking device presence
4.

Consider this Python code snippet intended to read from two I2C devices on the same bus:

import smbus2
bus = smbus2.SMBus(1)

value1 = bus.read_byte(0x20)
value2 = bus.read_byte(0x20)
print(value1, value2)

Why might this code cause a problem when trying to read two different devices?

medium
A. The code is missing pull-up resistors on the bus.
B. Both reads use the same address, so the second device is never accessed.
C. The addresses 0x20 and 0x20 are invalid on the bus.
D. The bus object is created twice, causing conflict.

Solution

  1. Step 1: Check device addresses used in reads

    Both read_byte calls use address 0x20, so only one device is accessed twice.
  2. Step 2: Understand impact on multiple devices

    To read two different devices, their unique addresses must be used; otherwise, the second device is ignored.
  3. Final Answer:

    Both reads use the same address, so the second device is never accessed. -> Option B
  4. Quick Check:

    Same address twice = one device only [OK]
Hint: Use different addresses to access multiple devices [OK]
Common Mistakes:
  • Assuming bus object creation causes error
  • Thinking addresses 0x20 are invalid
  • Confusing hardware wiring issues with code errors
5.

You have three I2C sensors connected to the same Raspberry Pi bus with addresses 0x20, 0x21, and 0x20. You want to read data from all three devices. What is the best way to fix this setup?

hard
A. Use separate I2C buses for devices with the same address.
B. Use software to ignore address conflicts and read anyway.
C. Connect devices with the same address to different GPIO pins.
D. Change the address of one device so all three have unique addresses.

Solution

  1. Step 1: Identify address conflict

    Two devices share address 0x20, causing bus conflicts and communication errors.
  2. Step 2: Resolve conflict by changing address

    Most I2C devices allow changing their address via hardware pins or software configuration to ensure uniqueness.
  3. Step 3: Alternative solutions

    Using separate buses or GPIO pins is complex; ignoring conflicts causes errors.
  4. Final Answer:

    Change the address of one device so all three have unique addresses. -> Option D
  5. Quick Check:

    Unique addresses fix conflicts [OK]
Hint: Ensure all devices have unique addresses to avoid conflicts [OK]
Common Mistakes:
  • Trying to read devices with duplicate addresses
  • Assuming software can fix hardware address conflicts
  • Using separate GPIO pins without separate buses
Recommended

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10 questions~5 mineasy hard