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Raspberry Piprogramming~10 mins

Button press detection in Raspberry Pi - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to import the GPIO library.

Raspberry Pi
import [1]
Drag options to blanks, or click blank then click option'
Atime
BRPi.GPIO
Cgpiozero
Dos
Attempts:
3 left
💡 Hint
Common Mistakes
Importing 'time' instead of the GPIO library.
Using 'os' which is unrelated to GPIO control.
2fill in blank
medium

Complete the code to set the GPIO mode to BCM numbering.

Raspberry Pi
GPIO.setmode([1])
Drag options to blanks, or click blank then click option'
AGPIO.BCM
BGPIO.BOARD
CGPIO.OUT
DGPIO.IN
Attempts:
3 left
💡 Hint
Common Mistakes
Using GPIO.BOARD which refers to physical pin numbers.
Using GPIO.OUT or GPIO.IN which are for pin direction.
3fill in blank
hard

Fix the error in setting up pin 17 as input with pull-up resistor.

Raspberry Pi
GPIO.setup(17, [1], pull_up_down=GPIO.PUD_UP)
Drag options to blanks, or click blank then click option'
AGPIO.IN
BGPIO.PUD_DOWN
CGPIO.OUT
DGPIO.PUD_OFF
Attempts:
3 left
💡 Hint
Common Mistakes
Using GPIO.OUT instead of GPIO.IN.
Confusing pull-up/down constants with pin direction.
4fill in blank
hard

Fill both blanks to read the button state and print if pressed.

Raspberry Pi
button_state = GPIO.input([1])
if button_state == [2]:
    print('Button pressed!')
Drag options to blanks, or click blank then click option'
A17
BGPIO.LOW
CGPIO.HIGH
D18
Attempts:
3 left
💡 Hint
Common Mistakes
Checking for GPIO.HIGH instead of GPIO.LOW.
Using wrong pin number like 18.
5fill in blank
hard

Fill all three blanks to set up a button press event detection with a callback.

Raspberry Pi
def button_callback(channel):
    print('Button was pressed!')

GPIO.setup([1], GPIO.IN, pull_up_down=GPIO.PUD_UP)
GPIO.add_event_detect([2], GPIO.FALLING, callback=[3], bouncetime=200)
Drag options to blanks, or click blank then click option'
A17
Bbutton_callback
CGPIO.RISING
DGPIO.FALLING
Attempts:
3 left
💡 Hint
Common Mistakes
Using GPIO.RISING instead of GPIO.FALLING for button press.
Using different pin numbers in setup and event detection.
Not passing the callback function correctly.

Practice

(1/5)
1. What does setting a Raspberry Pi GPIO pin as input with a pull-up resistor do when detecting a button press?
easy
A. It keeps the pin at HIGH until the button connects it to LOW when pressed.
B. It keeps the pin at LOW until the button connects it to HIGH when pressed.
C. It disables the pin to save power when the button is not pressed.
D. It makes the pin output a signal when the button is pressed.

Solution

  1. Step 1: Understand pull-up resistor behavior

    A pull-up resistor keeps the input pin at a HIGH voltage level by default.
  2. Step 2: Detect button press effect on pin

    When the button is pressed, it connects the pin to ground, making the input LOW.
  3. Final Answer:

    It keeps the pin at HIGH until the button connects it to LOW when pressed. -> Option A
  4. Quick Check:

    Pull-up resistor means default HIGH, press pulls LOW [OK]
Hint: Pull-up means default HIGH, press pulls pin LOW [OK]
Common Mistakes:
  • Thinking pull-up sets pin LOW by default
  • Confusing input with output pin modes
  • Assuming button press sets pin HIGH
2. Which of the following is the correct Python code snippet to set GPIO pin 17 as input with a pull-up resistor on Raspberry Pi?
easy
A. GPIO.setup(17, GPIO.IN, pull_up_down=GPIO.PUD_UP)
B. GPIO.setup(17, GPIO.OUT, pull_up_down=GPIO.PUD_UP)
C. GPIO.setup(17, GPIO.IN)
D. GPIO.setup(17, GPIO.OUT)

Solution

  1. Step 1: Identify pin mode for button input

    Button pins must be set as input to read their state.
  2. Step 2: Add pull-up resistor parameter

    Use pull_up_down=GPIO.PUD_UP to enable internal pull-up resistor.
  3. Final Answer:

    GPIO.setup(17, GPIO.IN, pull_up_down=GPIO.PUD_UP) -> Option A
  4. Quick Check:

    Input pin with pull-up resistor = GPIO.IN + PUD_UP [OK]
Hint: Input pin with pull-up uses GPIO.IN and PUD_UP [OK]
Common Mistakes:
  • Using GPIO.OUT instead of GPIO.IN
  • Omitting pull_up_down parameter
  • Setting pull-up resistor on output pin
3. What will be the output of this Python code snippet when the button connected to GPIO 18 is pressed?
import RPi.GPIO as GPIO
import time

GPIO.setmode(GPIO.BCM)
GPIO.setup(18, GPIO.IN, pull_up_down=GPIO.PUD_UP)

if GPIO.input(18) == GPIO.LOW:
    print("Button Pressed")
else:
    print("Button Not Pressed")
medium
A. No output
B. Button Not Pressed
C. SyntaxError
D. Button Pressed

Solution

  1. Step 1: Understand pin setup and input reading

    Pin 18 is set as input with pull-up resistor, so default is HIGH.
  2. Step 2: Check condition when button is pressed

    Pressing button pulls pin LOW, so condition GPIO.input(18) == GPIO.LOW is True.
  3. Final Answer:

    Button Pressed -> Option D
  4. Quick Check:

    Pressed button pulls pin LOW, prints "Button Pressed" [OK]
Hint: Pressed button reads LOW on pull-up input pin [OK]
Common Mistakes:
  • Assuming pressed button reads HIGH
  • Confusing pull-up with pull-down resistor
  • Expecting syntax or runtime errors
4. Identify the error in this Raspberry Pi button press detection code:
import RPi.GPIO as GPIO
import time

GPIO.setmode(GPIO.BCM)
GPIO.setup(23, GPIO.IN, pull_up_down=GPIO.PUD_UP)

while True:
    if GPIO.input(23) == GPIO.HIGH:
        print("Button Pressed")
    time.sleep(0.1)
medium
A. time.sleep(0.1) should be before the if statement.
B. The pull_up_down parameter is missing in GPIO.setup.
C. The code should check for GPIO.LOW to detect button press.
D. GPIO.setmode(GPIO.BCM) is incorrect and should be GPIO.BOARD.

Solution

  1. Step 1: Review button wiring and logic

    With pull-up resistor, button press pulls pin LOW, not HIGH.
  2. Step 2: Check condition in if statement

    Code incorrectly checks for GPIO.HIGH to detect press; should check GPIO.LOW.
  3. Final Answer:

    The code should check for GPIO.LOW to detect button press. -> Option C
  4. Quick Check:

    Pull-up input reads LOW when pressed, so check GPIO.LOW [OK]
Hint: Pressed button reads LOW on pull-up input pin [OK]
Common Mistakes:
  • Checking for HIGH instead of LOW on button press
  • Forgetting pull_up_down parameter
  • Misplacing sleep causing missed presses
5. You want to detect a button press on GPIO 21 and print "Pressed" only once per press, avoiding multiple prints while the button is held down. Which code snippet correctly implements this behavior?
import RPi.GPIO as GPIO
import time

GPIO.setmode(GPIO.BCM)
GPIO.setup(21, GPIO.IN, pull_up_down=GPIO.PUD_UP)

pressed = False
while True:
    if GPIO.input(21) == GPIO.LOW and not pressed:
        print("Pressed")
        pressed = True
    elif GPIO.input(21) == GPIO.HIGH:
        pressed = False
    time.sleep(0.05)
hard
A. This code never prints anything because pressed is always True.
B. This code prints "Pressed" once per press and avoids repeats while held.
C. This code prints "Pressed" continuously while button is held down.
D. This code causes a syntax error due to missing colon.

Solution

  1. Step 1: Understand the pressed flag usage

    The variable 'pressed' tracks if the button press was already detected to avoid repeats.
  2. Step 2: Analyze the if-elif logic

    When button is LOW and not pressed, it prints once and sets pressed True; when released (HIGH), resets pressed to False.
  3. Final Answer:

    This code prints "Pressed" once per press and avoids repeats while held. -> Option B
  4. Quick Check:

    pressed flag prevents multiple prints during hold [OK]
Hint: Use a flag variable to print once per press [OK]
Common Mistakes:
  • Printing inside loop without flag causes repeated prints
  • Not resetting flag on button release
  • Syntax errors from missing colons or indentation
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10 questions~5 mineasy hard