Bird
Raised Fist0
PLC Programmingscripting~5 mins

PID function block for process control in PLC Programming - Cheat Sheet & Quick Revision

Choose your learning style10 modes available
Recall & Review
beginner
What does PID stand for in process control?
PID stands for Proportional, Integral, and Derivative. These are the three control actions used to maintain a process variable at a desired setpoint.
Click to reveal answer
beginner
What is the role of the Proportional part in a PID controller?
The Proportional part produces an output proportional to the current error (difference between setpoint and process variable). It helps reduce the error quickly.
Click to reveal answer
intermediate
How does the Integral part of a PID controller improve control?
The Integral part sums past errors over time to eliminate steady-state error, ensuring the process variable reaches and stays at the setpoint.
Click to reveal answer
intermediate
What is the purpose of the Derivative part in a PID controller?
The Derivative part predicts future error by calculating the rate of change of the error. It helps reduce overshoot and improves system stability.
Click to reveal answer
beginner
In a PID function block, what are the typical inputs and outputs?
Typical inputs are Setpoint (desired value), Process Variable (measured value), and tuning parameters (Kp, Ki, Kd). The output is the control signal sent to the actuator.
Click to reveal answer
Which PID component helps eliminate steady-state error?
AProportional
BDerivative
CFeedforward
DIntegral
What does the derivative term in a PID controller do?
ASums past errors
BPredicts future error by rate of change
CCorrects current error proportionally
DSets the desired value
In a PID function block, which input represents the actual measured value?
AProcess Variable
BTuning Parameter
CControl Output
DSetpoint
What is the main purpose of a PID controller in process control?
ATo start the machine
BTo measure temperature
CTo maintain a process variable at a setpoint
DTo log data
Which tuning parameter controls the strength of the proportional action?
AKp
BKi
CKd
DKv
Explain how the three parts of a PID controller work together to control a process.
Think about how each part reacts to error differently.
You got /4 concepts.
    Describe the typical inputs and outputs of a PID function block in a PLC program.
    Consider what the controller needs to work and what it produces.
    You got /4 concepts.

      Practice

      (1/5)
      1. What is the main purpose of a PID function block in process control?
      easy
      A. To keep a process variable close to a desired target value
      B. To store data for later analysis
      C. To display process values on a screen
      D. To manually adjust valves and switches

      Solution

      1. Step 1: Understand the role of PID blocks

        PID blocks automatically adjust outputs to keep a process variable near a setpoint.
      2. Step 2: Compare options to this role

        Only To keep a process variable close to a desired target value describes this automatic control function; others describe unrelated tasks.
      3. Final Answer:

        To keep a process variable close to a desired target value -> Option A
      4. Quick Check:

        PID controls process variable = keep near target [OK]
      Hint: PID blocks control variables automatically, not manually [OK]
      Common Mistakes:
      • Thinking PID stores data instead of controlling
      • Confusing PID with display or manual control
      • Assuming PID only measures values
      2. Which of the following is the correct way to declare a PID function block instance named pid1 in a PLC program?
      easy
      A. pid1 : PID;
      B. pid1 = PID();
      C. PID pid1;
      D. pid1 -> PID();

      Solution

      1. Step 1: Recall PLC function block declaration syntax

        In PLC languages like Structured Text, function blocks are declared with name : Type;.
      2. Step 2: Match options to this syntax

        pid1 : PID; matches the correct syntax; others use incorrect assignment or C-like syntax.
      3. Final Answer:

        pid1 : PID; -> Option A
      4. Quick Check:

        Function block declaration uses colon and semicolon [OK]
      Hint: Use colon and semicolon to declare function blocks [OK]
      Common Mistakes:
      • Using equal sign instead of colon
      • Using C or Java style declarations
      • Using arrow operator incorrectly
      3. Given the following PLC code snippet using a PID block:
      pid1.Kp := 2.0;
      pid1.Ki := 0.5;
      pid1.Kd := 0.1;
      pid1.SetPoint := 100;
      pid1.ProcessVariable := 90;
      pid1();
      Output := pid1.ControlOutput;

      What is the expected behavior of Output after this code runs once?
      medium
      A. Output will be negative to decrease the process variable
      B. Output will be zero because PID needs multiple cycles
      C. Output will be a positive value to increase the process variable
      D. Output will equal the SetPoint value

      Solution

      1. Step 1: Analyze PID inputs and error

        The error is SetPoint (100) minus ProcessVariable (90) = 10, positive error.
      2. Step 2: Understand PID output direction

        Positive error means output should increase to raise the process variable, so output is positive.
      3. Final Answer:

        Output will be a positive value to increase the process variable -> Option C
      4. Quick Check:

        Positive error -> positive output to correct [OK]
      Hint: Positive error means output pushes variable up [OK]
      Common Mistakes:
      • Assuming output is zero on first run
      • Confusing output direction with error sign
      • Thinking output equals setpoint directly
      4. Identify the error in this PID block usage snippet:
      pid1.Kp := 1.5;
      pid1.Ki := 0.3;
      pid1.Kd := 0.05;
      pid1.SetPoint := 50;
      pid1.ProcessVariable := 55;
      Output := pid1.ControlOutput;
      pid1();
      medium
      A. Assigning ProcessVariable before SetPoint
      B. Setting Kp, Ki, Kd values too low
      C. Missing declaration of pid1
      D. Calling the PID block function pid1() after reading output

      Solution

      1. Step 1: Check order of function call and output read

        The PID block must be called (executed) before reading ControlOutput to update output.
      2. Step 2: Identify the mistake in code order

        Here, Output is assigned before pid1() is called, so output is stale or invalid.
      3. Final Answer:

        Calling the PID block function pid1() after reading output -> Option D
      4. Quick Check:

        Call PID block before reading output [OK]
      Hint: Always call PID block before reading output [OK]
      Common Mistakes:
      • Reading output before calling PID block
      • Confusing parameter order
      • Ignoring function block declaration
      5. You want to tune a PID block to control temperature in a tank. The temperature rises too slowly and overshoots the target. Which tuning change should you make to reduce overshoot and improve response?
      hard
      A. Decrease Kp and increase Ki
      B. Decrease Kp and increase Kd
      C. Increase Kp and decrease Kd
      D. Increase Ki and Kd equally

      Solution

      1. Step 1: Understand overshoot and slow rise causes

        High Kp causes overshoot; low Kd means less damping; slow rise means Kp might be too low.
      2. Step 2: Choose tuning to reduce overshoot and improve speed

        Decreasing Kp reduces overshoot; increasing Kd adds damping to reduce oscillations and overshoot.
      3. Final Answer:

        Decrease Kp and increase Kd -> Option B
      4. Quick Check:

        Lower Kp + higher Kd = less overshoot, better control [OK]
      Hint: Lower Kp and raise Kd to reduce overshoot [OK]
      Common Mistakes:
      • Increasing Kp causes more overshoot
      • Ignoring derivative gain effect
      • Changing Ki without addressing overshoot
      Recommended

      Ready to prove it?

      Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

      10 questions~5 mineasy hard