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IOT Protocolsdevops~10 mins

Block-wise transfer for large payloads in IOT Protocols - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to set the block size for block-wise transfer.

IOT Protocols
block_size = [1]  # Set block size in bytes
Drag options to blanks, or click blank then click option'
A1024
B512
C2048
D256
Attempts:
3 left
💡 Hint
Common Mistakes
Choosing a block size too small or too large can cause inefficiency or errors.
2fill in blank
medium

Complete the code to calculate the number of blocks needed for a payload.

IOT Protocols
num_blocks = (payload_size + [1] - 1) // [1]
Drag options to blanks, or click blank then click option'
Ablock_size
Bchunk_size
Cmax_block
Dpayload_size
Attempts:
3 left
💡 Hint
Common Mistakes
Using payload_size instead of block_size causes incorrect calculation.
3fill in blank
hard

Fix the error in the block number calculation for the last block.

IOT Protocols
last_block_num = total_blocks [1] 1
Drag options to blanks, or click blank then click option'
A*
B+
C//
D-
Attempts:
3 left
💡 Hint
Common Mistakes
Adding 1 instead of subtracting causes out-of-range block number.
4fill in blank
hard

Fill both blanks to correctly create a block option header with block number and size.

IOT Protocols
block_option = ([1] << 4) | [2]  # Compose block option value
Drag options to blanks, or click blank then click option'
Ablock_num
Bblock_size_code
Cpayload_len
Dblock_index
Attempts:
3 left
💡 Hint
Common Mistakes
Swapping block number and size code causes incorrect header.
5fill in blank
hard

Fill all three blanks to extract block number and size code from block option.

IOT Protocols
block_num = (block_option >> [1]) & [2]
block_size_code = block_option & [3]
Drag options to blanks, or click blank then click option'
A4
B0x0F
C0xF0
D8
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong shift or mask values leads to incorrect extraction.

Practice

(1/5)
1. What is the main purpose of block-wise transfer in IoT protocols?
easy
A. To compress data to save bandwidth
B. To split large data into smaller blocks for easier transmission
C. To encrypt data before sending
D. To prioritize urgent messages over others

Solution

  1. Step 1: Understand the problem of large data in IoT

    Large data can be hard to send in one go because devices have limited memory and networks can be unstable.
  2. Step 2: Identify the role of block-wise transfer

    Block-wise transfer breaks big data into smaller blocks, making it easier and safer to send piece by piece.
  3. Final Answer:

    To split large data into smaller blocks for easier transmission -> Option B
  4. Quick Check:

    Block-wise transfer = splitting data [OK]
Hint: Block-wise means breaking big data into small pieces [OK]
Common Mistakes:
  • Confusing block-wise transfer with encryption
  • Thinking it compresses data
  • Assuming it prioritizes messages
2. Which of the following is the correct format to indicate a block-wise transfer request with block number 3 and more blocks to come in CoAP?
easy
A. Block1: num=3; more=1; size=64
B. Block2: num=3; more=1; size=64
C. Block2: num=3; more=0; size=64
D. Block2: num=1; more=3; size=64

Solution

  1. Step 1: Identify the correct block option name

    In CoAP, Block1 is used for block-wise transfer of request payloads, and Block2 for responses. Since this is a request, Block1 is correct.
  2. Step 2: Check block number and more flag

    Block number is 3, 'more' flag is 1 meaning more blocks follow, and size is 64 bytes. Block1: num=3; more=1; size=64 matches all correctly.
  3. Final Answer:

    Block1: num=3; more=1; size=64 -> Option A
  4. Quick Check:

    Block1 with num=3 and more=1 means block 3 with more blocks [OK]
Hint: Block1 is for request blocks; 'more=1' means more blocks coming [OK]
Common Mistakes:
  • Using Block2 instead of Block1 for request
  • Setting 'more' flag to 0 when more blocks exist
  • Mixing block number and more flag values
3. Given the following CoAP block-wise transfer sequence, what is the block number of the last block received?
Block2: num=0; more=1; size=64
Block2: num=1; more=1; size=64
Block2: num=2; more=0; size=64
medium
A. 3
B. 1
C. 0
D. 2

Solution

  1. Step 1: Analyze the 'more' flag in each block

    Blocks 0 and 1 have 'more=1', meaning more blocks follow. Block 2 has 'more=0', meaning it is the last block.
  2. Step 2: Identify the last block number

    Since block number 2 has 'more=0', it is the last block received.
  3. Final Answer:

    2 -> Option D
  4. Quick Check:

    Last block has more=0 and num=2 [OK]
Hint: 'more=0' means last block number is current num [OK]
Common Mistakes:
  • Choosing block with more=1 as last block
  • Confusing block numbers with sequence count
  • Ignoring the 'more' flag
4. A device is sending a large payload using block-wise transfer but the receiver never acknowledges block number 2. What is the most likely cause of the problem?
medium
A. The sender did not set the 'more' flag correctly for block 2
B. The receiver has limited memory and dropped block 2
C. The sender skipped sending block 2
D. The block size is too large for the network

Solution

  1. Step 1: Understand the role of acknowledgments in block-wise transfer

    Each block must be acknowledged by the receiver to confirm it was received correctly.
  2. Step 2: Analyze why block 2 is not acknowledged

    If block 2 is never acknowledged, it likely means the sender never sent it, causing the receiver to wait indefinitely.
  3. Final Answer:

    The sender skipped sending block 2 -> Option C
  4. Quick Check:

    No ack for block means block not sent [OK]
Hint: Missing ack usually means block was never sent [OK]
Common Mistakes:
  • Blaming 'more' flag for missing ack
  • Assuming receiver dropped block without evidence
  • Thinking block size alone causes missing ack
5. You need to send a 200-byte payload using block-wise transfer with a block size of 64 bytes. How many blocks will be sent, and what will be the 'more' flag value for the last block?
hard
A. 4 blocks; 'more' flag = 0 on last block
B. 3 blocks; 'more' flag = 1 on last block
C. 4 blocks; 'more' flag = 1 on last block
D. 3 blocks; 'more' flag = 0 on last block

Solution

  1. Step 1: Calculate number of blocks needed

    Payload size is 200 bytes, block size is 64 bytes. 200 / 64 = 3.125, so 4 blocks are needed to send all data.
  2. Step 2: Determine 'more' flag for last block

    For all blocks except the last, 'more' flag is 1. For the last block, it is 0 to indicate no more blocks follow.
  3. Final Answer:

    4 blocks; 'more' flag = 0 on last block -> Option A
  4. Quick Check:

    Payload/size = 4 blocks; last block more=0 [OK]
Hint: Divide payload by block size, last block 'more' = 0 [OK]
Common Mistakes:
  • Rounding down number of blocks
  • Setting 'more' flag to 1 on last block
  • Ignoring partial block for last piece
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