[Solved] What will be the output of this FreeRTOS code snippet if both tasks print their names repeatedly?void Task1(void *pvParameters) { for (;;) { printf("Task1 running\n");... | FreeRTOS

FreeRTOS - Task Creation and Management

What will be the output of this FreeRTOS code snippet if both tasks print their names repeatedly?

void Task1(void *pvParameters) {
  for (;;) {
    printf("Task1 running\n");
    vTaskDelay(1000 / portTICK_PERIOD_MS);
  }
}

void Task2(void *pvParameters) {
  for (;;) {
    printf("Task2 running\n");
    vTaskDelay(500 / portTICK_PERIOD_MS);
  }
}

ABoth tasks print at the same rate

BTask1 prints twice as often as Task2

COnly Task1 prints because it has higher priority

DTask2 prints twice as often as Task1

Step-by-Step Solution

Solution:

Step 1: Analyze vTaskDelay times
Task1 delays 1000ms, Task2 delays 500ms, so Task2 wakes twice as often.
Step 2: Understand print frequency
Task2 prints every 500ms, Task1 every 1000ms, so Task2 prints twice as often.
Final Answer:
Task2 prints twice as often as Task1 -> Option D
Quick Check:
Delay time inversely affects print frequency [OK]

Quick Trick: Shorter delay means more frequent task execution [OK]

Common Mistakes:

Assuming same print rate despite different delays
Ignoring delay units and timing
Assuming priority affects print frequency here

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More FreeRTOS Quizzes

What will be the output of this FreeRTOS code snippet if both tasks print their names repeatedly?

Step 1: Analyze vTaskDelay times

Step 2: Understand print frequency

Final Answer:

Quick Check:

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