[Solved] Consider this code snippet in FreeRTOS: TickType_t start = xTaskGetTickCount(); vTaskDelay(50); TickType_t end = xTaskGetTickCount(); TickType_t diff = end - start; What is the expected value of diff? | FreeRTOS

FreeRTOS - RTOS Fundamentals

Consider this code snippet in FreeRTOS:

TickType_t start = xTaskGetTickCount();
vTaskDelay(50);
TickType_t end = xTaskGetTickCount();
TickType_t diff = end - start;

What is the expected value of diff?

A0

B50

C100

DDepends on task priority

Step-by-Step Solution

Solution:

Step 1: Understand xTaskGetTickCount()
This function returns the current tick count since the scheduler started.
Step 2: Analyze vTaskDelay(50)
The task delays itself for 50 ticks, so the tick count advances by 50 during the delay.
Step 3: Calculate difference
Subtracting start from end gives the delay duration, which should be 50 ticks.
Final Answer:
50 -> Option B
Quick Check:
Delay ticks = 50 [OK]

Quick Trick: Delay of 50 ticks means tick count difference is 50 [OK]

Common Mistakes:

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