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Embedded Cprogramming~10 mins

Single channel ADC reading in Embedded C - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to start the ADC conversion.

Embedded C
ADC_Start([1]);
Drag options to blanks, or click blank then click option'
AADC1
BADC2
CADC3
DADC4
Attempts:
3 left
💡 Hint
Common Mistakes
Using an uninitialized ADC channel.
Passing an incorrect channel name.
2fill in blank
medium

Complete the code to check if the ADC conversion is complete.

Embedded C
if (ADC_GetFlagStatus([1]) == SET) { /* conversion done */ }
Drag options to blanks, or click blank then click option'
AADC_FLAG_AWD
BADC_FLAG_OVR
CADC_FLAG_STRT
DADC_FLAG_EOC
Attempts:
3 left
💡 Hint
Common Mistakes
Checking the wrong flag like overrun or start flags.
Confusing flag names.
3fill in blank
hard

Fix the error in reading the ADC value.

Embedded C
uint16_t adcValue = [1]();
Drag options to blanks, or click blank then click option'
AADC_ReadValue
BADC_GetValue
CADC_GetConversionValue
DADC_Read
Attempts:
3 left
💡 Hint
Common Mistakes
Using a non-existent or incorrect function name.
Confusing reading and starting functions.
4fill in blank
hard

Fill both blanks to create a dictionary comprehension that maps channel numbers to their ADC values if the value is above 1000.

Embedded C
adc_results = { [1]: [2] for [1] in channels if [2] > 1000 }
Drag options to blanks, or click blank then click option'
Ach
Badc_value
Cvalue
Dchannel
Attempts:
3 left
💡 Hint
Common Mistakes
Using the same variable name for both blanks.
Using undefined variable names.
5fill in blank
hard

Fill all three blanks to create a dictionary comprehension that maps channel names in uppercase to their ADC values if the value is greater than 2000.

Embedded C
adc_data = { [1].[2](): [3] for [1] in channels if [3] > 2000 }
Drag options to blanks, or click blank then click option'
Ach
Bupper
Cadc_val
Dvalue
Attempts:
3 left
💡 Hint
Common Mistakes
Using incorrect method names.
Mixing variable names.

Practice

(1/5)
1. What does a single channel ADC do in embedded C programming?
easy
A. It reads one analog input and converts it to a digital number.
B. It writes digital data to an analog output.
C. It reads multiple analog inputs simultaneously.
D. It converts digital signals to analog signals.

Solution

  1. Step 1: Understand ADC function

    An ADC (Analog to Digital Converter) converts analog signals to digital numbers.
  2. Step 2: Identify single channel meaning

    Single channel means it reads only one analog input at a time.
  3. Final Answer:

    It reads one analog input and converts it to a digital number. -> Option A
  4. Quick Check:

    Single channel ADC = One analog input read [OK]
Hint: Single channel ADC reads one input only [OK]
Common Mistakes:
  • Confusing ADC with DAC
  • Thinking ADC reads multiple inputs at once
  • Mixing analog output with input reading
2. Which of the following is the correct way to start an ADC conversion in embedded C?
easy
A. ADC_Stop();
B. ADC_StartConversion();
C. ADC_Read();
D. ADC_Init();

Solution

  1. Step 1: Identify function to start ADC

    Starting ADC conversion usually requires a function like ADC_StartConversion().
  2. Step 2: Differentiate other functions

    ADC_Read() reads the value, ADC_Init() initializes hardware, ADC_Stop() stops ADC.
  3. Final Answer:

    ADC_StartConversion(); -> Option B
  4. Quick Check:

    Start ADC = ADC_StartConversion() [OK]
Hint: Start ADC with ADC_StartConversion() [OK]
Common Mistakes:
  • Using ADC_Read() to start conversion
  • Confusing initialization with start
  • Calling ADC_Stop() instead of start
3. What will be the output of this code snippet if the ADC reads a value of 512?
int adcValue = ADC_Read();
printf("ADC Value: %d\n", adcValue);
medium
A. ADC Value: 0
B. ADC Value: 1023
C. ADC Value: 512
D. ADC Value: -512

Solution

  1. Step 1: Understand ADC_Read() output

    ADC_Read() returns the current digital value from ADC, here given as 512.
  2. Step 2: Print the value

    printf prints the integer value stored in adcValue, which is 512.
  3. Final Answer:

    ADC Value: 512 -> Option C
  4. Quick Check:

    ADC_Read() = 512 printed as is [OK]
Hint: ADC_Read() returns current ADC number [OK]
Common Mistakes:
  • Assuming ADC_Read() returns max value always
  • Confusing negative values in ADC reading
  • Printing wrong variable or format
4. Identify the error in this ADC reading code:
ADC_Init();
int value = ADC_Read();
ADC_StartConversion();
printf("Value: %d", value);
medium
A. Variable 'value' should be float
B. ADC_Init() is missing
C. printf format specifier is wrong
D. ADC_StartConversion() should be called before ADC_Read()

Solution

  1. Step 1: Check ADC function order

    ADC_StartConversion() must be called before ADC_Read() to start conversion.
  2. Step 2: Analyze code sequence

    Here, ADC_Read() is called before starting conversion, so it reads old or invalid data.
  3. Final Answer:

    ADC_StartConversion() should be called before ADC_Read() -> Option D
  4. Quick Check:

    Start conversion before reading ADC [OK]
Hint: Start ADC conversion before reading value [OK]
Common Mistakes:
  • Reading ADC before starting conversion
  • Ignoring initialization step
  • Wrong printf format for int
5. You want to read an analog sensor value using a single channel ADC and convert it to voltage (0-5V) with 10-bit resolution. Which code snippet correctly calculates the voltage?
int adcValue = ADC_Read();
float voltage = ?;
hard
A. voltage = (adcValue / 1023.0) * 5.0;
B. voltage = (adcValue * 5) / 1023;
C. voltage = adcValue * 5.0 / 1024.0;
D. voltage = (adcValue / 1024) * 5;

Solution

  1. Step 1: Understand ADC resolution and voltage range

    10-bit ADC means values from 0 to 1023 represent 0 to 5 volts.
  2. Step 2: Calculate voltage correctly

    Voltage = (adcValue / 1023.0) * 5.0; uses floating division and full scale 1023.
  3. Final Answer:

    voltage = (adcValue / 1023.0) * 5.0; -> Option A
  4. Quick Check:

    Voltage = ADC value / max * 5V [OK]
Hint: Divide by 1023.0 for 10-bit ADC voltage calc [OK]
Common Mistakes:
  • Dividing by 1024 instead of 1023
  • Using integer division instead of float
  • Multiplying before dividing causing wrong result
Recommended

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10 questions~5 mineasy hard