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Drone Programmingprogramming~10 mins

Color-based tracking in Drone Programming - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to initialize the camera for color tracking.

Drone Programming
camera = DroneCamera([1]=True)
Drag options to blanks, or click blank then click option'
Athermal_vision
Bnight_mode
Ccolor_tracking
Dauto_focus
Attempts:
3 left
💡 Hint
Common Mistakes
Using night_mode instead of color_tracking disables color detection.
2fill in blank
medium

Complete the code to set the target color for tracking.

Drone Programming
tracker.set_target_color([1])
Drag options to blanks, or click blank then click option'
A'blue'
B'red'
C'ultraviolet'
D'infrared'
Attempts:
3 left
💡 Hint
Common Mistakes
Choosing 'infrared' or 'ultraviolet' which are not visible colors.
3fill in blank
hard

Fix the error in the code to correctly start the color tracking process.

Drone Programming
drone.[1]()
Drag options to blanks, or click blank then click option'
Astart_tracking
Bbegin_tracking
Cinitiate_follow
Dtrack_color
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'begin_tracking' or 'track_color' which are not valid methods.
4fill in blank
hard

Fill both blanks to create a dictionary that maps detected colors to drone commands.

Drone Programming
commands = { [1]: 'move_left', [2]: 'move_right' }
Drag options to blanks, or click blank then click option'
A'red'
B'green'
C'blue'
D'yellow'
Attempts:
3 left
💡 Hint
Common Mistakes
Swapping colors or using colors not in the options.
5fill in blank
hard

Fill all three blanks to filter detected colors and execute commands only if confidence is high.

Drone Programming
if detected_color == [1] and confidence [2] [3]:
    execute_command(commands[detected_color])
Drag options to blanks, or click blank then click option'
A'red'
B>
C0.8
D'green'
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong color or comparison operator, or missing the confidence threshold.

Practice

(1/5)
1. What is the main purpose of color-based tracking in drone programming?
easy
A. To make the drone follow an object by detecting its color
B. To control the drone's altitude using GPS
C. To improve the drone's battery life
D. To send commands to the drone via remote control

Solution

  1. Step 1: Understand color-based tracking concept

    Color-based tracking means the drone uses color detection to follow an object.
  2. Step 2: Identify the main goal

    The goal is to detect and follow an object by its color, not altitude or battery.
  3. Final Answer:

    To make the drone follow an object by detecting its color -> Option A
  4. Quick Check:

    Color-based tracking = follow object by color [OK]
Hint: Focus on color detection as the tracking method [OK]
Common Mistakes:
  • Confusing color tracking with GPS control
  • Thinking it manages battery or remote commands
  • Mixing color tracking with altitude control
2. Which of the following code snippets correctly initializes a color filter for red in a drone's tracking system?
easy
A. red_filter = {'lower': (0, 255, 255), 'upper': (10, 100, 100)}
B. red_filter = {'lower': [100, 0, 0], 'upper': [255, 10, 10]}
C. red_filter = {'low': (0, 100, 100), 'high': (10, 255, 255)}
D. red_filter = {'lower': (0, 100, 100), 'upper': (10, 255, 255)}

Solution

  1. Step 1: Check correct keys for filter dictionary

    The keys should be 'lower' and 'upper' to define color range.
  2. Step 2: Verify value types and ranges

    Values must be tuples with HSV ranges; red_filter = {'lower': (0, 100, 100), 'upper': (10, 255, 255)} uses correct keys and tuples.
  3. Final Answer:

    red_filter = {'lower': (0, 100, 100), 'upper': (10, 255, 255)} -> Option D
  4. Quick Check:

    Correct keys and tuple values = red_filter = {'lower': (0, 100, 100), 'upper': (10, 255, 255)} [OK]
Hint: Look for 'lower' and 'upper' keys with tuple HSV values [OK]
Common Mistakes:
  • Using wrong dictionary keys like 'low' or 'high'
  • Using lists instead of tuples for HSV values
  • Swapping lower and upper HSV ranges
3. Given the following code snippet for detecting a blue object, what will be printed if the detected object's center is at (150, 200)?
blue_filter = {'lower': (100, 150, 0), 'upper': (140, 255, 255)}
object_center = (150, 200)
if 100 <= object_center[0] <= 140:
    print('Blue object detected at', object_center)
else:
    print('No blue object detected')
medium
A. Blue object detected at (150, 200)
B. SyntaxError
C. No blue object detected
D. RuntimeError

Solution

  1. Step 1: Check the condition on x-coordinate

    Condition checks if 100 <= 150 <= 140, which is false because 150 > 140.
  2. Step 2: Determine which print executes

    Since condition is false, else block runs printing 'No blue object detected'.
  3. Final Answer:

    No blue object detected -> Option C
  4. Quick Check:

    150 not in 100-140 range = No detection [OK]
Hint: Check numeric range conditions carefully [OK]
Common Mistakes:
  • Assuming 150 is within 100 to 140 range
  • Confusing syntax errors with logic errors
  • Ignoring else block output
4. The following code is intended to detect a green object and print its position, but it raises an error. What is the error and how to fix it?
green_filter = {'lower': (40, 50, 50), 'upper': (80, 255, 255)}
object_center = None
if green_filter['lower'][0] <= object_center[0] <= green_filter['upper'][0]:
    print('Green object at', object_center)
else:
    print('No green object detected')
medium
A. SyntaxError due to incorrect dictionary keys; fix keys to 'low' and 'high'
B. TypeError because object_center is None; fix by assigning a tuple to object_center
C. IndexError because green_filter keys are missing; add keys
D. No error; code runs correctly

Solution

  1. Step 1: Identify the error cause

    object_center is None, so accessing object_center[0] causes TypeError.
  2. Step 2: Fix the error

    Assign a tuple like (x, y) to object_center before using it in condition.
  3. Final Answer:

    TypeError because object_center is None; fix by assigning a tuple to object_center -> Option B
  4. Quick Check:

    None used as index causes TypeError [OK]
Hint: Check variable types before indexing [OK]
Common Mistakes:
  • Ignoring NoneType indexing error
  • Changing dictionary keys incorrectly
  • Assuming code runs without error
5. You want the drone to follow a yellow object but only if its detected center's y-coordinate is above 100. Which code snippet correctly implements this condition using color-based tracking?
yellow_filter = {'lower': (20, 100, 100), 'upper': (30, 255, 255)}
object_center = (120, 150)

# Choose the correct condition to check
hard
A. if yellow_filter['lower'][0] <= object_center[0] <= yellow_filter['upper'][0] and object_center[1] > 100: print('Following yellow object')
B. if yellow_filter['lower'][1] <= object_center[1] <= yellow_filter['upper'][1] and object_center[0] > 100: print('Following yellow object')
C. if yellow_filter['lower'][0] <= object_center[1] <= yellow_filter['upper'][0] and object_center[0] > 100: print('Following yellow object')
D. if yellow_filter['lower'][1] <= object_center[0] <= yellow_filter['upper'][1] and object_center[1] > 100: print('Following yellow object')

Solution

  1. Step 1: Understand HSV and coordinate roles

    yellow_filter keys 'lower' and 'upper' define hue range at index 0; object_center[0] is x, object_center[1] is y.
  2. Step 2: Check condition for hue and y-coordinate

    Hue check uses object_center[0] between lower and upper hue; y-coordinate must be > 100.
  3. Final Answer:

    if yellow_filter['lower'][0] <= object_center[0] <= yellow_filter['upper'][0] and object_center[1] > 100: print('Following yellow object') -> Option A
  4. Quick Check:

    Hue range on x and y > 100 condition = if yellow_filter['lower'][0] <= object_center[0] <= yellow_filter['upper'][0] and object_center[1] > 100: print('Following yellow object') [OK]
Hint: Match hue with x, check y > 100 separately [OK]
Common Mistakes:
  • Mixing x and y coordinates in conditions
  • Using wrong indices for hue or saturation
  • Checking y-coordinate against hue range
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10 questions~5 mineasy hard