Coordinates and parameters for drawing a line using direct distance entry in AutoCAD.
| Cell | Value |
|---|---|
| A1 | Start Point X |
| B1 | Start Point Y |
| A2 | 0 |
| B2 | 0 |
| A3 | Distance |
| B3 | Angle (degrees) |
| A4 | 5 |
| B4 | 45 |
| A5 | End Point X |
| B5 | End Point Y |
Coordinates and parameters for drawing a line using direct distance entry in AutoCAD.
| Cell | Value |
|---|---|
| A1 | Start Point X |
| B1 | Start Point Y |
| A2 | 0 |
| B2 | 0 |
| A3 | Distance |
| B3 | Angle (degrees) |
| A4 | 5 |
| B4 | 45 |
| A5 | End Point X |
| B5 | End Point Y |
End Point X = Start Point X + Distance * COS(Angle)
End Point Y = Start Point Y + Distance * SIN(Angle)A B 1 |Start X|Start Y| 2 | 0 | 0 | 3 |Distance| Angle | 4 | 5 | 45 | 5 | End X | End Y | 6 | | |
A B 1 |Start X|Start Y| 2 | 0 | 0 | 3 |Distance| Angle | 4 | 5 | 45 | 5 | 3.54 | 3.54 |
What is the main purpose of Direct distance entry in AutoCAD?
Which of the following is the correct way to use direct distance entry when drawing a line in AutoCAD?
In AutoCAD, you start drawing a line from point (0,0). You move the cursor to the right and type 5 using direct distance entry, then press Enter. What will be the coordinates of the new point?
You try to use direct distance entry by typing a length but nothing happens. What is the most likely reason?
You want to draw a line starting at (2,3) that is exactly 10 units long at a 45-degree angle using direct distance entry. Which sequence of actions will achieve this?
Pass the test and this pattern moves unknown