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Arduinoprogramming~10 mins

ISR best practices in Arduino - Step-by-Step Execution

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Concept Flow - ISR best practices in Arduino
Interrupt Occurs
CPU Pauses Main Code
Jump to ISR Function
Execute ISR Quickly
Clear Interrupt Flag
Return to Main Code
Resume Main Code Execution
When an interrupt happens, the main program pauses, runs the ISR quickly, then resumes the main code.
Execution Sample
Arduino
volatile int count = 0;

void ISR() {
  count++;
}

void setup() {
  attachInterrupt(digitalPinToInterrupt(2), ISR, RISING);
}

void loop() {
  // main code here
}
This code sets up an interrupt on pin 2 that increases count each time the pin signal rises.
Execution Table
StepEventMain Code StateISR ActionVariable ChangesReturn to Main Code
1Main code runningcount=0No ISRcount=0Continue main code
2Interrupt on pin 2 risingcount=0ISR calledcount=1Resume main code
3Main code runningcount=1No ISRcount=1Continue main code
4Interrupt on pin 2 risingcount=1ISR calledcount=2Resume main code
5Main code runningcount=2No ISRcount=2Continue main code
ExitNo more interruptscount=2No ISRcount=2Program runs normally
💡 No more interrupts occur, main code runs continuously.
Variable Tracker
VariableStartAfter 1After 2Final
count0122
Key Moments - 3 Insights
Why must ISR functions be very short and fast?
Because during ISR execution, the main program is paused (see execution_table steps 2 and 4). Long ISRs delay the main code and can cause missed interrupts.
Why is the variable 'count' declared as volatile?
Volatile tells the compiler the variable can change anytime (like in ISR). Without volatile, the main code might not see updates made inside ISR (see variable_tracker).
Can we use delay() or Serial.print() inside ISR?
No, these functions are slow and can cause problems inside ISR. ISR should only do quick, simple tasks (see concept_flow).
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table at step 2, what is the value of 'count' after ISR runs?
A1
B0
C2
DUndefined
💡 Hint
Check the 'Variable Changes' column at step 2 in execution_table.
At which step does the main code resume after the ISR finishes?
AStep 2
BStep 3
CStep 1
DStep 4
💡 Hint
Look at the 'Return to Main Code' column in execution_table after ISR actions.
If 'count' was not declared volatile, what might happen?
AISR would not run
BProgram would crash
CMain code might not see updated 'count'
DInterrupts would be disabled
💡 Hint
Refer to variable_tracker and key_moments about volatile keyword.
Concept Snapshot
ISR best practices in Arduino:
- Keep ISR functions very short and fast.
- Use volatile for variables shared with ISR.
- Avoid delay(), Serial.print(), or heavy code inside ISR.
- Clear interrupt flags if needed.
- Main code pauses during ISR and resumes after.
- Use attachInterrupt() to link ISR to pin events.
Full Transcript
In Arduino, when an interrupt happens, the main program pauses and runs a special function called ISR (Interrupt Service Routine). The ISR should be very short and fast to avoid delaying the main program. Variables shared between ISR and main code must be declared volatile so the main code always sees the latest value. Functions like delay() or Serial.print() should not be used inside ISR because they are slow. After ISR finishes, the main program resumes where it left off. This example shows an interrupt on pin 2 that increases a count variable each time the pin signal rises. The execution table traces how the count changes and when the ISR runs. Remember, keeping ISRs quick and using volatile variables are key best practices.