v-for for list rendering in Vue - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to render a list of items using v-for.

Vue

<ul>
  <li v-for="item in [1]" :key="item.id">{{ item.name }}</li>
</ul>

Drag options to blanks, or click blank then click option'

Aitems

Blist

Cdata

Delements

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name that does not exist in the component data.

Forgetting to add a unique key with :key.

The v-for directive loops over the array named items to render each item.

2fill in blank

medium

Complete the code to include the index when rendering the list with v-for.

Vue

<ul>
  <li v-for="(item, [1]) in items" :key="item.id">{{ index + 1 }}. {{ item.name }}</li>
</ul>

Drag options to blanks, or click blank then click option'

Aidx

Bindex

Ci

Dcount

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name not declared in the v-for syntax.

Forgetting parentheses around both variables.

The second variable in v-for is the index, commonly named index.

3fill in blank

hard

Fix the error in the v-for syntax to correctly render the list.

Vue

<ul>
  <li v-for="item [1] items" :key="item.id">{{ item.name }}</li>
</ul>

Drag options to blanks, or click blank then click option'

Aon

Bof

Cin

Dat

Attempts:

3 left

💡 Hint

Common Mistakes

Using of instead of in in v-for.

Missing the keyword entirely.

The correct syntax for v-for uses in to loop over an array.

4fill in blank

hard

Fill both blanks to render a list of users with their index and unique key.

Vue

<ul>
  <li v-for="(user, [1]) in [2]" :key="user.id">{{ index + 1 }}. {{ user.name }}</li>
</ul>

Drag options to blanks, or click blank then click option'

Aindex

Bi

Cusers

Ditems

Attempts:

3 left

💡 Hint

Common Mistakes

Swapping the index and array names.

Using a variable name not declared in the component.

The index variable is index and the array is users.

5fill in blank

hard

Fill all three blanks to render a list of products showing their uppercase names and filtering only available ones.

Vue

<ul>
  <li v-for="(product, [1]) in products.filter(p => p.available)" :key="[2]">{{ product.[3] }}</li>
</ul>

Drag options to blanks, or click blank then click option'

Aindex

Bproduct.id

Cname.toUpperCase()

Di

Attempts:

3 left

💡 Hint

Common Mistakes

Using a non-unique key or missing the key.

Not calling the uppercase function correctly.

Using wrong variable names.

The index variable is i, the key is product.id, and the displayed name is the uppercase version using name.toUpperCase().

Practice

1. What does the v-for directive do in Vue.js?

easy

A. It repeats an element or component for each item in a list.

B. It conditionally shows or hides an element.

C. It binds a value to an input element.

D. It listens for user events like clicks.

Solution

1. Step 1: Understand the purpose of v-for

   The v-for directive is used to loop over arrays or objects and render elements multiple times.

2. Step 2: Compare with other directives

   Other directives like v-if control visibility, v-bind binds data, and v-on listens to events, so they do not repeat elements.

3. Final Answer:

   It repeats an element or component for each item in a list. -> Option A

4. Quick Check:

   v-for = repeat elements [OK]

Hint: Remember: v-for means 'for each' in a list [OK]

Common Mistakes:

• Confusing v-for with v-if for conditional rendering
• Thinking v-for binds data instead of looping
• Mixing v-for with event listeners like v-on

2. Which of the following is the correct syntax to render a list of items using v-for in Vue?

easy

A. <li v-for="item of items">{{ item }}</li>

B. <li v-for="items in item">{{ item }}</li>

C. <li v-for="item in items">{{ item }}</li>

D. <li v-for="items of item">{{ items }}</li>

Solution

1. Step 1: Identify correct v-for syntax

   The correct syntax is v-for="item in items" where items is the array and item is the loop variable.

2. Step 2: Check each option

   <li v-for="item in items">{{ item }}</li> uses correct syntax and variable names. Options B, C, and D have incorrect order or variable names.

3. Final Answer:

   <li v-for="item in items">{{ item }}</li> -> Option C

4. Quick Check:

   Use v-for="item in items" [OK]

Hint: Use 'item in items' to loop correctly [OK]

Common Mistakes:

• Swapping 'item' and 'items' in the syntax
• Using 'of' instead of 'in' (Vue uses 'in')
• Using plural for loop variable instead of singular

3. Given the Vue template:

<ul>
  <li v-for="(fruit, index) in fruits" :key="index">{{ index }} - {{ fruit }}</li>
</ul>

and the data:

fruits: ['Apple', 'Banana', 'Cherry']

What will be the rendered output?

medium

A. index - fruitindex - fruitindex - fruit

B. Apple - 0Banana - 1Cherry - 2

C. AppleBananaCherry

D. 0 - Apple1 - Banana2 - Cherry

Solution

1. Step 1: Understand the loop variables

   The v-for uses (fruit, index) in fruits, so index is the position and fruit is the item.

2. Step 2: Substitute values in template

   Each
3. shows "index - fruit". For the array ['Apple', 'Banana', 'Cherry'], indexes are 0,1,2 respectively.

4. Final Answer:

   <ul><li>0 - Apple</li><li>1 - Banana</li><li>2 - Cherry</li></ul> -> Option D

5. Quick Check:

   Index and fruit displayed correctly [OK]

Hint: Remember: (item, index) in list shows index first [OK]

Common Mistakes:

• Mixing order of index and item in output
• Forgetting to use :key with index
• Assuming 'of' works instead of 'in'

4. What is wrong with this Vue template snippet?

<ul>
  <li v-for="item in items">{{ item }}</li>
</ul>

Given the data:

items: null

What will happen when Vue tries to render this?

medium

A. It will render nothing without error.

B. It will throw a runtime error because items is null.

C. It will render one empty list item.

D. It will render the string 'null' inside a list item.

Solution

1. Step 1: Understand v-for expects iterable data

   The v-for directive requires an array or object to loop over. If items is null, it is not iterable.

2. Step 2: Predict Vue behavior on null

   Vue will throw a runtime error because it cannot iterate over null.

3. Final Answer:

   It will throw a runtime error because items is null. -> Option B

4. Quick Check:

   v-for needs iterable data [OK]

Hint: v-for needs arrays or objects, not null [OK]

Common Mistakes:

• Assuming null renders empty list silently
• Expecting v-for to handle null gracefully
• Confusing null with empty array []

5. You have a nested array of user objects grouped by city:

const usersByCity = {
  'New York': [{ id: 1, name: 'Alice' }, { id: 2, name: 'Bob' }],
  'Paris': [{ id: 3, name: 'Claire' }]
}

How do you use v-for to render a list showing city names and their users' names inside each city?

hard

A. <div v-for="(users, city) in usersByCity" :key="city">
<h3>{{ city }}</h3>
<ul>
<li v-for="user in users" :key="user.id">{{ user.name }}</li>
</ul>
</div>

B. <div v-for="city in usersByCity" :key="city">
<h3>{{ city }}</h3>
<ul>
<li v-for="user in city" :key="user.id">{{ user.name }}</li>
</ul>
</div>

C. <div v-for="(city, users) in usersByCity" :key="city">
<h3>{{ city }}</h3>
<ul>
<li v-for="user in users" :key="user.id">{{ user.name }}</li>
</ul>
</div>

D. <div v-for="user in usersByCity" :key="user.id">
<h3>{{ user.city }}</h3>
<ul>
<li>{{ user.name }}</li>
</ul>
</div>

Solution

1. Step 1: Understand the data structure

   usersByCity is an object where keys are city names and values are arrays of user objects.

2. Step 2: Use v-for to loop over object entries

   Use v-for="(users, city) in usersByCity" to get city name and users array. Then loop over users array inside.

3. Step 3: Check options for correct variable order and keys

   <div v-for="(users, city) in usersByCity" :key="city"> <h3>{{ city }}</h3> <ul> <li v-for="user in users" :key="user.id">{{ user.name }}</li> </ul> </div> correctly uses (users, city) and nested v-for with keys. <div v-for="(city, users) in usersByCity" :key="city"> <h3>{{ city }}</h3> <ul> <li v-for="user in users" :key="user.id">{{ user.name }}</li> </ul> </div> swaps city and users order incorrectly. Options B and D misuse variables.

4. Final Answer:

   Option A code snippet correctly renders cities and their users. -> Option A

5. Quick Check:

   Object loop: (value, key) = (users, city) [OK]

Hint: For objects, v-for uses (value, key) in object [OK]

Common Mistakes:

• Swapping key and value order in v-for
• Using array syntax for object iteration
• Missing unique :key on nested loops