Pattern matching with template literals in Typescript - Mini Project: Build & Apply

Pattern Matching with Template Literals in TypeScript

📋 What You'll Learn

💡 Why This Matters

🌍 Real World

Pattern matching with template literals helps in validating codes, IDs, or formatted strings in many applications like form validation or data filtering.

💼 Career

Understanding pattern matching and template literals is useful for frontend and backend developers to handle string data efficiently and write clean, readable code.

1

Create the array of strings

Create an array called codes with these exact string values: 'abc123', 'xyz789', 'abc456', 'def123', 'abc789'.

Typescript

# Create the array called codes with the exact strings
# Your code here

Hint

Use square brackets [] to create an array and separate strings with commas.

2

Create the pattern string with template literals

Create a constant string called pattern using template literals that matches strings starting with 'abc' and ending with any three digits. Use the template literal syntax with backticks and a placeholder for the digits as ${'\d\d\d'}.

Typescript

const codes = ['abc123', 'xyz789', 'abc456', 'def123', 'abc789'];
// Create the pattern string called pattern using template literals
// Your code here

Hint

Use backticks ` to create a template literal. Use ${} to insert a pattern for three digits as a string.

3

Filter strings matching the pattern

Create a new array called matchingCodes by filtering codes. Use the filter method with a function that uses a regular expression to test if each code matches the pattern ^abc\d{3}$. Use the exact variable names matchingCodes and codes.

Typescript

const codes = ['abc123', 'xyz789', 'abc456', 'def123', 'abc789'];
const pattern = `abc${'\d\d\d'}`;
// Filter codes to create matchingCodes array using regex
// Your code here

Hint

Use filter with a function that returns true if the code matches the regex /^abc\d{3}$/.

4

Print the matching codes

Use console.log to print the matchingCodes array.

Typescript

const codes = ['abc123', 'xyz789', 'abc456', 'def123', 'abc789'];
const pattern = `abc${'\d\d\d'}`;
const matchingCodes = codes.filter(code => /^abc\d{3}$/.test(code));
// Print the matchingCodes array
# Your code here

Hint

Use console.log(matchingCodes); to show the filtered array.

Practice

1. What does pattern matching with template literals in TypeScript primarily help you do?

easy

A. Create new variables dynamically

B. Automatically generate functions from strings

C. Change the type of a variable at runtime

D. Check if a string fits a specific shape or format

Solution

1. Step 1: Understand the purpose of pattern matching

   Pattern matching with template literals is used to verify if strings follow a certain pattern or format.

2. Step 2: Relate to template literals usage

   Template literals allow embedding expressions and patterns to check string shapes easily.

3. Final Answer:

   Check if a string fits a specific shape or format -> Option D

4. Quick Check:

   Pattern matching = Check string shape [OK]

Hint: Pattern matching checks string shapes, not variable types [OK]

Common Mistakes:

• Confusing pattern matching with variable creation
• Thinking it changes variable types
• Assuming it generates functions automatically

2. Which of the following is the correct syntax to use a template literal pattern in a TypeScript type check?

easy

A. type ID = `${string}-${number}`;

B. type ID = '${string}-${number}';

C. ;`}rebmun{$-}gnirts{$` = DI epyt

D. type ID = `${string}-${number}`

Solution

1. Step 1: Identify correct template literal syntax

   Template literals use backticks (`) and embed types inside ${} without quotes.

2. Step 2: Check for correct punctuation

   type ID = `${string}-${number}`; correctly uses backticks and ${} with no extra quotes.

3. Final Answer:

   type ID = `${string}-${number}`; -> Option A

4. Quick Check:

   Backticks + ${} = correct syntax [OK]

Hint: Use backticks and ${} without quotes for template types [OK]

Common Mistakes:

• Using single or double quotes instead of backticks
• Putting quotes inside ${} expressions
• Missing backticks around the pattern

3. What will be the result of this TypeScript code snippet?

type Email = `${string}@${string}.com`;

function isEmail(value: string): value is Email {
  return /.+@.+\.com$/.test(value);
}

console.log(isEmail('[e-mail]'));
console.log(isEmail('[e-mail]'));

medium

A. true\ntrue

B. false\ntrue

C. true\nfalse

D. false\nfalse

Solution

1. Step 1: Understand the Email type pattern

   The Email type expects strings like '[e-mail]'.

2. Step 2: Analyze the isEmail function

   The regex checks if the string ends with '.com' after an '@' symbol.

3. Step 3: Check the console.log outputs

   '[e-mail]' matches the regex, so true; '[e-mail]' does not, so false.

4. Final Answer:

   true false -> Option C

5. Quick Check:

   Regex matches .com only = true, false [OK]

Hint: Regex matches only .com emails, others return false [OK]

Common Mistakes:

• Assuming .org matches .com pattern
• Ignoring regex anchors
• Confusing true/false order in output

4. Identify the error in this TypeScript code using template literal pattern matching:

type Phone = `${number}-${number}-${number}`;

function isPhone(value: string): value is Phone {
  return /^\d{3}-\d{3}-\d{4}$/.test(value);
}

medium

A. The Phone type pattern does not match the regex format

B. The regex pattern is missing anchors

C. Template literals cannot use number types inside ${}

D. The function should return a boolean, not a type predicate

Solution

1. Step 1: Compare Phone type and regex pattern

   Phone type expects three numbers separated by dashes, but each ${number} matches any number, not fixed digits.

2. Step 2: Check regex pattern details

   The regex expects exactly 3 digits, then 3 digits, then 4 digits, which doesn't align with the Phone type's generic number placeholders.

3. Final Answer:

   The Phone type pattern does not match the regex format -> Option A

4. Quick Check:

   Type pattern and regex must align [OK]

Hint: Match template literal types exactly with regex patterns [OK]

Common Mistakes:

• Assuming ${number} matches fixed digit counts
• Ignoring regex anchors (though present here)
• Confusing return type of type predicate functions

5. Given this TypeScript code, what will be the output?

type UserID = `user_${number}`;

function parseUserID(id: string): UserID | null {
  if (id.match(/^user_\d+$/)) {
    return id as UserID;
  }
  return null;
}

console.log(parseUserID('user_123'));
console.log(parseUserID('admin_123'));

hard

A. null\nnull

B. 'user_123'\nnull

C. 'user_123'\n'user_123'

D. null\n'user_123'

Solution

1. Step 1: Understand UserID type pattern

   UserID must start with 'user_' followed by a number.

2. Step 2: Analyze parseUserID function

   The function returns the id cast as UserID if it matches the regex /^user_\d+$/, else returns null.

3. Step 3: Evaluate console.log outputs

   'user_123' matches regex, so returns 'user_123'; 'admin_123' does not, so returns null.

4. Final Answer:

   'user_123' null -> Option B

5. Quick Check:

   Regex match returns id, else null [OK]

Hint: Regex match controls return; unmatched returns null [OK]

Common Mistakes:

• Assuming 'admin_123' matches user pattern
• Confusing return types with casting
• Ignoring regex anchors and pattern