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Typescriptprogramming~10 mins

ConstructorParameters type in Typescript - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to extract constructor parameter types using ConstructorParameters.

Typescript
type Params = [1]<Date>;
Drag options to blanks, or click blank then click option'
AReturnType
BParameters
CConstructorParameters
DInstanceType
Attempts:
3 left
💡 Hint
Common Mistakes
Using Parameters instead of ConstructorParameters
Using ReturnType which extracts return types
Using InstanceType which extracts instance types
2fill in blank
medium

Complete the code to define a class and extract its constructor parameter types.

Typescript
class Person {
  constructor(public name: string, public age: number) {}
}
type PersonParams = [1]<typeof Person>;
Drag options to blanks, or click blank then click option'
AConstructorParameters
BParameters
CReturnType
DInstanceType
Attempts:
3 left
💡 Hint
Common Mistakes
Using Parameters which works with functions, not constructors
Using InstanceType which gives the instance type, not parameters
3fill in blank
hard

Fix the error in the code to correctly extract constructor parameters of a class.

Typescript
class Car {
  constructor(make: string, year: number) {}
}
type CarParams = ConstructorParameters<[1]>;
Drag options to blanks, or click blank then click option'
Atypeof Car
BCar
CCarConstructor
DInstanceType<Car>
Attempts:
3 left
💡 Hint
Common Mistakes
Using the class name directly instead of typeof
Using InstanceType which is for instances, not constructors
4fill in blank
hard

Fill both blanks to create a function that accepts constructor parameters of a class.

Typescript
function createInstance(cls: [1], ...args: [2]) {
  return new cls(...args);
}
Drag options to blanks, or click blank then click option'
Anew (...args: any) => any
BConstructorParameters<typeof cls>
Dany[]
Attempts:
3 left
💡 Hint
Common Mistakes
Using instance type instead of constructor signature
Not using ConstructorParameters for the args
5fill in blank
hard

Fill all three blanks to define a generic function that creates instances using constructor parameters.

Typescript
function makeInstance<T extends [1]>(cls: T, ...args: [2]<T>): InstanceType<T> {
  return new cls(...args);
}

type Params<T> = [3]<T>;
Drag options to blanks, or click blank then click option'
Anew (...args: any) => any
BConstructorParameters
DParameters
Attempts:
3 left
💡 Hint
Common Mistakes
Using Parameters instead of ConstructorParameters
Not constraining T to a constructor signature

Practice

(1/5)
1.

What does the ConstructorParameters type utility do in TypeScript?

easy
A. Extracts the types of a class constructor's parameters as a tuple
B. Creates a new class with the same constructor parameters
C. Returns the return type of a class constructor
D. Converts constructor parameters into a union type

Solution

  1. Step 1: Understand the purpose of ConstructorParameters

    The ConstructorParameters utility extracts the types of the parameters used in a class constructor and returns them as a tuple type.
  2. Step 2: Compare with other options

    Options B, C, and D describe different behaviors that ConstructorParameters does not perform.
  3. Final Answer:

    Extracts the types of a class constructor's parameters as a tuple -> Option A
  4. Quick Check:

    ConstructorParameters = tuple of constructor args [OK]
Hint: Remember: ConstructorParameters gives constructor args as a tuple [OK]
Common Mistakes:
  • Confusing ConstructorParameters with ReturnType
  • Thinking it creates a new class
  • Assuming it returns a union type
2.

Which of the following is the correct syntax to get the constructor parameter types of a class MyClass using ConstructorParameters?

class MyClass { constructor(name: string, age: number) {} }
easy
A. type Params = ConstructorParameters<MyClass>;
B. type Params = ConstructorParameters;
C. type Params = ConstructorParameters;
D. type Params = ConstructorParameters;

Solution

  1. Step 1: Identify the correct type argument for ConstructorParameters

    The argument must be a constructor function type, which is typeof MyClass (the class constructor type), not the instance type.
  2. Step 2: Check each option

    type Params = ConstructorParameters<MyClass>; uses the instance type, which is incorrect. type Params = ConstructorParameters; uses a non-existent property. type Params = ConstructorParameters; uses invalid syntax. Only type Params = ConstructorParameters; correctly uses typeof MyClass.
  3. Final Answer:

    type Params = ConstructorParameters<typeof MyClass>; -> Option B
  4. Quick Check:

    Use typeof ClassName with ConstructorParameters [OK]
Hint: Use typeof ClassName to get constructor type [OK]
Common Mistakes:
  • Passing instance type instead of constructor type
  • Using invalid syntax like new expressions
  • Trying to access constructor property
3.

What is the output type of the following code?

class Person {
  constructor(public name: string, public age: number) {}
}

type Params = ConstructorParameters<typeof Person>;
medium
A. [string, string]
B. [name: string, age: number]
C. [string, number]
D. Error: ConstructorParameters cannot be applied

Solution

  1. Step 1: Analyze the constructor parameters

    The constructor takes two parameters: name of type string and age of type number.
  2. Step 2: Understand ConstructorParameters output

    ConstructorParameters<typeof Person> returns a tuple of the parameter types: [string, number].
  3. Final Answer:

    [string, number] -> Option C
  4. Quick Check:

    ConstructorParameters returns tuple of constructor arg types [OK]
Hint: ConstructorParameters returns tuple of constructor argument types [OK]
Common Mistakes:
  • Expecting parameter names in the tuple
  • Confusing parameter types with instance properties
  • Thinking it returns an error
4.

Identify the error in this code snippet:

class Car {
  constructor(make: string, year: number) {}
}

type Params = ConstructorParameters<Car>;
medium
A. Car is an instance type, should use typeof Car
B. ConstructorParameters cannot be used with classes
C. Constructor parameters must be public or private
D. Missing parentheses after Car in ConstructorParameters

Solution

  1. Step 1: Check the argument passed to ConstructorParameters

    The argument must be the constructor function type, which is typeof Car, not the instance type Car.
  2. Step 2: Identify the error

    Using Car directly causes a type error because it is the instance type, not the constructor type.
  3. Final Answer:

    Car is an instance type, should use typeof Car -> Option A
  4. Quick Check:

    Use typeof ClassName with ConstructorParameters [OK]
Hint: Always use typeof ClassName with ConstructorParameters [OK]
Common Mistakes:
  • Passing instance type instead of constructor type
  • Assuming ConstructorParameters works on instances
  • Adding parentheses after class name
5.

Given the following classes, how can you create a type alias EmployeeParams that matches the constructor parameters of Employee by reusing the constructor parameters of Person?

class Person {
  constructor(public name: string, public age: number) {}
}

class Employee extends Person {
  constructor(name: string, age: number, public salary: number) {
    super(name, age);
  }
}
hard
A. type EmployeeParams = ConstructorParameters<typeof Employee>;
B. type EmployeeParams = [string, number, number];
C. type EmployeeParams = ConstructorParameters<Person> & number;
D. type EmployeeParams = [...ConstructorParameters<typeof Person>, number];

Solution

  1. Step 1: Understand the constructor parameters

    Person constructor takes name and age. Employee adds salary as a third parameter.
  2. Step 2: Reuse Person's constructor parameters and add salary

    Using ConstructorParameters<typeof Person> gives [string, number]. Adding number for salary creates [string, number, number].
  3. Step 3: Check options

    type EmployeeParams = [...ConstructorParameters<typeof Person>, number]; correctly uses tuple spread to combine parameters. type EmployeeParams = ConstructorParameters<typeof Employee>; gets all parameters but does not reuse Person's. type EmployeeParams = ConstructorParameters<Person> & number; is invalid syntax. type EmployeeParams = [string, number, number]; hardcodes types without reuse.
  4. Final Answer:

    type EmployeeParams = [...ConstructorParameters<typeof Person>, number]; -> Option D
  5. Quick Check:

    Reuse constructor params with tuple spread [OK]
Hint: Use tuple spread to extend ConstructorParameters [OK]
Common Mistakes:
  • Not using typeof with class name
  • Hardcoding parameter types instead of reusing
  • Using invalid intersection (&) instead of tuple spread
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10 questions~5 mineasy hard