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Testing Fundamentalstesting~10 mins

Branch coverage in Testing Fundamentals - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to illustrate the branches in an if-else statement for branch coverage.

Testing Fundamentals
if condition:
    execute_true_branch()
else:
    execute_[1]_branch()
Drag options to blanks, or click blank then click option'
Afalse
Btrue
Cpath
Ddecision
Attempts:
3 left
💡 Hint
Common Mistakes
Forgetting to test the else branch
Assuming only the true branch matters
2fill in blank
medium

Complete the code to ensure branch coverage for a function with two conditions.

Testing Fundamentals
def check_values(a, b):
    if a > 0:
        return 'Positive'
    elif b [1] 0:
        return 'Non-positive b'
    else:
        return 'Other'
Drag options to blanks, or click blank then click option'
A>=
B!=
C<=
D==
Attempts:
3 left
💡 Hint
Common Mistakes
Using '==' which only checks for zero
Using '!=' which excludes zero
3fill in blank
hard

Fix the error in the branch coverage test condition.

Testing Fundamentals
if score [1] 50:
    print('Pass')
else:
    print('Fail')
Drag options to blanks, or click blank then click option'
A<
B>=
C=>
D==
Attempts:
3 left
💡 Hint
Common Mistakes
Using '=>' which is a syntax error
Using '==' which only checks equality
4fill in blank
hard

Fill both blanks to create a branch coverage test for a nested condition.

Testing Fundamentals
if temperature [1] 0:
    if weather [2] 'snowy':
        action = 'Stay inside'
    else:
        action = 'Go outside'
Drag options to blanks, or click blank then click option'
A>
B==
C!=
D<
Attempts:
3 left
💡 Hint
Common Mistakes
Using '>' instead of '<' for temperature
Using '!=' instead of '==' for weather
5fill in blank
hard

Fill all three blanks to complete a branch coverage test with a dictionary comprehension.

Testing Fundamentals
results = {test[1]: outcome for test, outcome in tests.items() if outcome [2] 'fail' and 'critical' [3] test}
Drag options to blanks, or click blank then click option'
A.upper()
B==
Cin
D.lower()
Attempts:
3 left
💡 Hint
Common Mistakes
Using .upper() instead of .lower()
Using '!=' instead of '==' for outcome
Using '==' instead of 'in' for test name check

Practice

(1/5)
1. What does branch coverage testing ensure in software testing?
easy
A. All possible paths of each decision point are tested
B. Only the main function is tested
C. All variables are initialized
D. The software runs faster

Solution

  1. Step 1: Understand branch coverage concept

    Branch coverage means testing every decision point in the code, including both true and false outcomes.
  2. Step 2: Match concept to options

    All possible paths of each decision point are tested correctly states that all possible paths of each decision point are tested, which is the essence of branch coverage.
  3. Final Answer:

    All possible paths of each decision point are tested -> Option A
  4. Quick Check:

    Branch coverage = all decision paths tested [OK]
Hint: Branch coverage tests both true and false paths [OK]
Common Mistakes:
  • Confusing branch coverage with statement coverage
  • Thinking it only tests main functions
  • Assuming it improves speed
2. Which of the following is the correct way to write a branch coverage test condition in pseudocode?
easy
A. print('Test complete')
B. while x > 10 do A
C. for i in range(10): do A
D. if (x > 10) then do A else do B

Solution

  1. Step 1: Identify branch decision structure

    Branch coverage requires a decision point with two or more paths, like an if-else condition.
  2. Step 2: Check options for decision points

    if (x > 10) then do A else do B shows an if-else statement, which has two branches (true and false). Other options do not have decision branches.
  3. Final Answer:

    if (x > 10) then do A else do B -> Option D
  4. Quick Check:

    If-else = branch decision [OK]
Hint: Look for if-else to identify branches [OK]
Common Mistakes:
  • Choosing loops as branch examples
  • Ignoring else part of if-else
  • Confusing print statements with branches
3. Consider the following code snippet:
if (a > 0) {
  if (b == 5) {
    print('Path 1');
  } else {
    print('Path 2');
  }
} else {
  print('Path 3');
}

How many test cases are needed for 100% branch coverage?
medium
A. 3
B. 4
C. 2
D. 5

Solution

  1. Step 1: Identify decision points and branches

    There are two if statements: outer (a > 0) with true/false branches, inner (b == 5) with true/false branches.
  2. Step 2: Count unique branches

    Outer if: 2 branches (true, false). Inner if (only if outer true): 2 branches. Total branches = 3 unique paths: Path 1, Path 2, Path 3.
  3. Final Answer:

    3 -> Option A
  4. Quick Check:

    Branches = 3 paths [OK]
Hint: Count all true/false branches in nested ifs [OK]
Common Mistakes:
  • Counting only outer if branches
  • Assuming each if adds 2 test cases independently
  • Ignoring nested structure
4. You have this code:
if (x != 0) {
  print('Non-zero');
}

A test case with x = 0 is missing. What branch coverage issue does this cause?
medium
A. True branch not tested
B. False branch not tested
C. Syntax error in code
D. All branches covered

Solution

  1. Step 1: Identify branches in the if condition

    The if condition has two branches: true (x != 0) and false (x == 0).
  2. Step 2: Analyze test cases given

    Only test cases with x != 0 exist, so true branch is tested but false branch (x == 0) is missing.
  3. Final Answer:

    False branch not tested -> Option B
  4. Quick Check:

    Missing false branch test = coverage gap [OK]
Hint: Test both true and false conditions for full coverage [OK]
Common Mistakes:
  • Assuming one test case covers all branches
  • Confusing true and false branches
  • Thinking missing test causes syntax error
5. Given this code:
if (score >= 90) {
  grade = 'A';
} else if (score >= 75) {
  grade = 'B';
} else {
  grade = 'C';
}

How many test cases are needed for 100% branch coverage?
hard
A. 2
B. 5
C. 3
D. 4

Solution

  1. Step 1: Identify all decision points and branches

    There are two if conditions: first (score >= 90) with true/false branches, second (score >= 75) with true/false branches inside else.
  2. Step 2: Count unique branches

    Branches: first if true (score>=90), first false + second true (75<=score<90), first false + second false (score<75). Total 3 test cases needed for 100% coverage.
  3. Final Answer:

    3 -> Option C
  4. Quick Check:

    if-else-if-else chain = 3 test cases [OK]
Hint: Count all true/false branches in if-else if-else chains [OK]
Common Mistakes:
  • Counting only if statements, ignoring else
  • Assuming 4 test cases are needed
  • Missing nested else if branches
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard