Why testing prevents costly failures in Testing Fundamentals - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print a message when a test fails.

Testing Fundamentals

if test_result == [1]:
    print("Test failed! Please fix the bug.")

Drag options to blanks, or click blank then click option'

A"passed"

B"fail"

C"success"

D"ok"

Attempts:

3 left

💡 Hint

Common Mistakes

Using "passed" or "success" will never trigger the failure message.

The test result should be compared to "fail" to detect a failure and print the message.

2fill in blank

medium

Complete the code to check if a bug is costly before reporting.

Testing Fundamentals

if bug_severity [1] 5:
    report_bug()

Drag options to blanks, or click blank then click option'

A<

B==

C>

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' will report less severe bugs, which is not the goal.

We report bugs with severity greater than 5 because they are costly.

3fill in blank

hard

Fix the error in the assertion to check if the function output is correct.

Testing Fundamentals

assert [1] == expected_output, "Output mismatch!"

Drag options to blanks, or click blank then click option'

Aresult

Binput

Cprint

Dlen

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'input' or 'print' causes errors or wrong checks.

The assertion compares the actual result to the expected output to detect errors.

4fill in blank

hard

Fill both blanks to create a test that checks if a number is positive and less than 100.

Testing Fundamentals

if number [1] 0 and number [2] 100:
    print("Valid number")

Drag options to blanks, or click blank then click option'

A>

B<=

C<

D>=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>=' or '<=' changes the range and may include invalid numbers.

The number must be greater than 0 and less than 100 to be valid.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps words to their lengths if length is greater than 3.

Testing Fundamentals

lengths = { [1]: [2] for [1] in words if len([1]) [3] 3 }

Drag options to blanks, or click blank then click option'

Aword

Blen(word)

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' will select short words, which is incorrect.

The comprehension uses 'word' as key, 'len(word)' as value, and filters words longer than 3 characters.