[Solved] Given this test code:def test_average(): numbers = [] avg = sum(numbers) / len(numbers) if numbers else 0 assert avg == 0What will happen when this test runs? | Testing Fundamentals

Testing Fundamentals - Why Software Testing Matters

Given this test code:

def test_average():
    numbers = []
    avg = sum(numbers) / len(numbers) if numbers else 0
    assert avg == 0

What will happen when this test runs?

AThe test passes but avg is None

BThe test fails due to division by zero error

CThe test raises a syntax error

DThe test passes because avg is correctly set to 0

Step-by-Step Solution

Solution:

Step 1: Analyze the code logic
Check if numbers list is empty; if so, avg is set to 0.
Step 2: Evaluate the assertion
Since numbers is empty, avg = 0, so assert avg == 0 passes.
Final Answer:
The test passes because avg is correctly set to 0 -> Option D
Quick Check:
Empty list handled safely with conditional expression [OK]

Quick Trick: Check for empty list before division to avoid errors [OK]

Common Mistakes:

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