Cost of bugs at different stages in Testing Fundamentals - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print the stage where bug fixing is cheapest.

Testing Fundamentals

print('Bug fixing is cheapest during the [1] stage.')

Drag options to blanks, or click blank then click option'

Arequirements

Bdeployment

Cproduction

Dmaintenance

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing 'production' or 'deployment' because bugs are found there, but fixing is more expensive then.

Fixing bugs early during the requirements stage is cheapest because changes are easier to make before coding starts.

2fill in blank

medium

Complete the sentence to show where bug fixing cost increases significantly.

Testing Fundamentals

Bug fixing cost increases significantly during the [1] phase.

Drag options to blanks, or click blank then click option'

Adesign

Brequirements

Ctesting

Ddeployment

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing 'design' because it is before coding, but cost is lower there.

The testing phase is when bugs are found after coding, so fixing them costs more than earlier stages.

3fill in blank

hard

Fix the error in the code to correctly calculate bug fixing cost multiplier.

Testing Fundamentals

cost_multiplier = 1 if stage == 'requirements' else [1]

Drag options to blanks, or click blank then click option'

A'10'

B10

Cten

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using a string '10' instead of number 10 causes type errors.

The cost multiplier should be a number, not a string or word. 10 is correct for later stages.

4fill in blank

hard

Fill both blanks to create a dictionary mapping stages to bug fixing costs.

Testing Fundamentals

bug_costs = {'requirements': 1, [1]: 10, [2]: 100}

Drag options to blanks, or click blank then click option'

A'testing'

B'deployment'

C'production'

D'design'

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'deployment' instead of 'production' for the highest cost.

Testing costs 10 times more, production costs 100 times more than requirements.

5fill in blank

hard

Fill all three blanks to complete the function that returns bug fixing cost multiplier by stage.

Testing Fundamentals

def get_bug_cost(stage):
    return [1].get(stage, [2]) * [3]

costs = {'requirements': 1, 'testing': 10, 'production': 100}

Drag options to blanks, or click blank then click option'

Acosts

B1

C2

Dcosts.get(stage)

Attempts:

3 left

💡 Hint

Common Mistakes

Using costs.get(stage) inside return without default causes errors if stage missing.

The function uses the costs dictionary, returns 1 if stage not found, and multiplies by 2 as an example factor.