Boundary value analysis in Testing Fundamentals - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define the minimum boundary value for testing.

Testing Fundamentals

min_value = [1]

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A1

B0

C-1

D100

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing 0 which might be invalid for this test case.

Choosing a negative number when only positive inputs are valid.

The minimum boundary value is often the smallest valid input, here it is 1.

2fill in blank

medium

Complete the code to define the maximum boundary value for testing.

Testing Fundamentals

max_value = [1]

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A99

B100

C101

D50

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing 101 which is outside the valid range.

Choosing 99 which is just below the maximum boundary.

The maximum boundary value is the largest valid input, which is 100 here.

3fill in blank

hard

Fix the error in the test case that checks the value just below the minimum boundary.

Testing Fundamentals

test_value = [1]

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A0

B1

C-1

D2

Attempts:

3 left

💡 Hint

Common Mistakes

Using -1 which might be out of expected input domain.

Using 1 which is the minimum boundary, not below it.

The value just below the minimum boundary (1) is 0, which is used to test invalid input below the boundary.

4fill in blank

hard

Fill both blanks to create a test case dictionary with boundary values and their expected results.

Testing Fundamentals

test_cases = [1]: [2]

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A{'min': 1, 'max': 100}

B{'min': 0, 'max': 101}

C{'pass', 'fail'}

D{'valid', 'invalid'}

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing keys and values incorrectly.

Using invalid boundary values in the keys.

The test_cases dictionary uses the correct boundary values as keys and expected results as values.

5fill in blank

hard

Fill all three blanks to complete the function that returns True if input is within boundary values.

Testing Fundamentals

def is_within_boundary(value):
    return [1] <= value [2] [3]

Drag options to blanks, or click blank then click option'

A1

B<=

C100

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' instead of '<=' for the upper boundary.

Swapping the boundary values.

The function checks if the value is greater than or equal to 1 and less than or equal to 100.