Numeric functions (min, max, ceil) in Terraform - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to find the minimum of two numbers.

Terraform

output "min_value" {
  value = min(10, [1])
}

Drag options to blanks, or click blank then click option'

A30

B5

C15

D20

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing a number larger than 10.

Confusing min with max function.

The min function returns the smallest number. Here, 5 is smaller than 10.

2fill in blank

medium

Complete the code to find the maximum of three numbers.

Terraform

output "max_value" {
  value = max(7, 14, [1])
}

Drag options to blanks, or click blank then click option'

A20

B5

C10

D12

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing a number smaller than 14.

Using min instead of max function.

The max function returns the largest number. Among 7, 14, and 20, 20 is the largest.

3fill in blank

hard

Fix the error in the code to correctly round up the number.

Terraform

output "rounded_up" {
  value = ceil([1])
}

Drag options to blanks, or click blank then click option'

A3

B"3.2"

C3.2

Dceil

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a string instead of a number.

Passing the function name instead of a number.

The ceil function rounds a number up. It requires a numeric input, not a string or function name.

4fill in blank

hard

Fill both blanks to create a value that is the maximum of 5 and the ceiling of 4.3.

Terraform

output "max_ceil" {
  value = max([1], ceil([2]))
}

Drag options to blanks, or click blank then click option'

A5

B4.3

C3.7

D6

Attempts:

3 left

💡 Hint

Common Mistakes

Using a number other than 5 in the first blank.

Using a number other than 4.3 in the second blank.

The code finds the maximum between 5 and the ceiling of 4.3 (which is 5). So both blanks must be 5 and 4.3 respectively.

5fill in blank

hard

Fill all three blanks to output the minimum of the ceiling of 7.1, the maximum of 3 and 9, and 8.

Terraform

output "complex_calc" {
  value = min(ceil([1]), max([2], [3]), 8)
}

Drag options to blanks, or click blank then click option'

A7.1

B3

C9

D6

Attempts:

3 left

💡 Hint

Common Mistakes

Swapping the numbers in max function.

Using wrong numbers for ceiling or max.

The ceiling of 7.1 is 8. The maximum of 3 and 9 is 9. The minimum among 8, 9, and 8 is 8.