Protocol composition in practice in Swift - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is protocol composition in Swift?

Protocol composition lets you combine multiple protocols into one requirement, so a type must conform to all of them at once.

beginner

How do you write a protocol composition type in Swift?

Use the syntax: ProtocolA & ProtocolB to require a type that conforms to both ProtocolA and ProtocolB.

intermediate

Why use protocol composition instead of inheritance?

Protocol composition allows combining behaviors from multiple protocols without needing a class hierarchy, making code more flexible and reusable.

beginner

Example: What does this mean?
func performAction(on object: Drawable & Animatable)

The function requires an object that conforms to both Drawable and Animatable protocols, so it can draw and animate the object.

intermediate

Can protocol composition be used with class-only protocols?

Yes, you can combine class-only protocols using protocol composition, and the resulting type will also be class-constrained.

Which syntax correctly represents protocol composition in Swift?

A ProtocolA + ProtocolB

B ProtocolA | ProtocolB

C ProtocolA, ProtocolB

D ProtocolA & ProtocolB

Protocol composition uses the & symbol to combine protocols.

What does a function parameter typed as Readable & Writable require?

A An object that is both Readable and Writable

B An object that is only Readable

C An object that is neither Readable nor Writable

D An object that is either Readable or Writable

The & means the object must conform to both protocols.

Can protocol composition be used with structs in Swift?

A No, only classes can use protocol composition

B Only enums can use protocol composition

C Yes, any type can conform to multiple protocols

D Only protocols can use protocol composition

Structs can conform to multiple protocols and be used with protocol composition.

What is a benefit of using protocol composition?

A It allows combining multiple behaviors flexibly

B It forces inheritance from a single class

C It restricts types to only one protocol

D It replaces all protocols with classes

Protocol composition lets you combine multiple protocols for flexible design.

If a protocol is class-only, what happens when you compose it with another protocol?

A The composition is no longer class-only

B The composition remains class-only

C The composition becomes a struct

D The composition is invalid

Class-only constraints carry over in protocol composition.

Explain how protocol composition works in Swift and give a simple example.

Think about how you can require multiple behaviors at once.

Describe a real-life scenario where protocol composition would be useful in Swift programming.

Imagine an object that needs to do more than one thing.

Practice

1. What does protocol composition in Swift allow you to do?

easy

A. Combine multiple protocols into one requirement without creating a new protocol

B. Create a new class that inherits from multiple classes

C. Define a protocol with stored properties

D. Override methods in a protocol extension

Solution

1. Step 1: Understand protocol composition concept

   Protocol composition uses the & operator to require multiple protocols at once without defining a new protocol.

2. Step 2: Compare options with concept

   Only Combine multiple protocols into one requirement without creating a new protocol correctly describes combining multiple protocols without creating a new one. Other options describe unrelated or incorrect Swift features.

3. Final Answer:

   Combine multiple protocols into one requirement without creating a new protocol -> Option A

4. Quick Check:

   Protocol composition = Combine protocols [OK]

Hint: Remember & means combine protocols, not inherit classes [OK]

Common Mistakes:

• Confusing protocol composition with class inheritance
• Thinking protocols can have stored properties
• Believing protocol extensions override methods

2. Which of the following is the correct syntax to declare a function parameter that requires both Codable and Equatable protocols using protocol composition?

easy

A. func save(item: Codable | Equatable) {}

B. func save(item: Codable & Equatable) {}

C. func save(item: Codable, Equatable) {}

D. func save(item: Codable && Equatable) {}

Solution

1. Step 1: Recall protocol composition syntax

   Swift uses & to combine protocols in type requirements, like Codable & Equatable.

2. Step 2: Evaluate each option

   func save(item: Codable & Equatable) {} uses correct & syntax. func save(item: Codable | Equatable) {} uses | which is invalid. func save(item: Codable, Equatable) {} uses comma which is invalid. func save(item: Codable && Equatable) {} uses && which is invalid.

3. Final Answer:

   func save(item: Codable & Equatable) {} -> Option B

4. Quick Check:

   Use & to combine protocols [OK]

Hint: Use & to combine protocols, not |, comma, or && [OK]

Common Mistakes:

• Using | or && instead of & for protocol composition
• Separating protocols with commas in parameter types
• Confusing logical operators with protocol composition

3. What will be the output of the following Swift code?

protocol A { func foo() }
protocol B { func bar() }
struct MyStruct: A, B {
  func foo() { print("foo") }
  func bar() { print("bar") }
}
func callBoth(item: A & B) {
  item.foo()
  item.bar()
}
let obj = MyStruct()
callBoth(item: obj)

medium

A. foo\nbar

B. foo

C. bar

D. Compilation error

Solution

1. Step 1: Understand protocol composition usage

   The function callBoth requires an argument conforming to both A and B. MyStruct conforms to both.

2. Step 2: Trace function calls

   Inside callBoth, foo() prints "foo" and bar() prints "bar". Both are called in order.

3. Final Answer:

   foo bar -> Option A

4. Quick Check:

   Both protocol methods called = foo\nbar [OK]

Hint: Both protocols' methods run in order when composed [OK]

Common Mistakes:

• Assuming only one protocol method runs
• Expecting a compile error due to protocol composition
• Confusing protocol conformance with inheritance

4. Identify the error in this Swift code using protocol composition:

protocol P1 { func p1Method() }
protocol P2 { func p2Method() }
func testFunc(param: P1 & P2) {
  param.p1Method()
  param.p2Method()
}
struct S: P1 {
  func p1Method() { print("P1") }
}
let s = S()
testFunc(param: s)

medium

A. Method p2Method is missing in testFunc

B. Function testFunc has wrong parameter syntax

C. Protocols P1 and P2 cannot be combined

D. Struct S does not conform to protocol P2

Solution

1. Step 1: Check struct conformance

   Struct S conforms only to P1, missing P2 conformance.

2. Step 2: Analyze function parameter requirement

   Function testFunc requires a parameter conforming to both P1 and P2. Passing s fails because s lacks P2.

3. Final Answer:

   Struct S does not conform to protocol P2 -> Option D

4. Quick Check:

   Missing protocol conformance causes error [OK]

Hint: Check all protocols are conformed before passing composed type [OK]

Common Mistakes:

• Assuming partial protocol conformance is enough
• Thinking function parameter syntax is incorrect
• Believing protocols cannot be combined with &

5. Given these protocols and structs:

protocol Drawable { func draw() }
protocol Colorable { var color: String { get } }
struct Circle: Drawable, Colorable {
  var color: String
  func draw() { print("Drawing a circle") }
}
struct Square: Drawable {
  func draw() { print("Drawing a square") }
}

Which of the following function signatures correctly accepts only objects that are both Drawable and Colorable?

hard

A. func render(item: Drawable) { item.draw() }

B. func render(item: Drawable | Colorable) { item.draw() }

C. func render(item: Drawable & Colorable) { item.draw(); print(item.color) }

D. func render(item: Colorable) { print(item.color) }

Solution

1. Step 1: Understand protocol composition for parameters

   To accept only objects conforming to both Drawable and Colorable, use Drawable & Colorable.

2. Step 2: Check each function signature

   func render(item: Drawable & Colorable) { item.draw(); print(item.color) } uses correct composition and accesses both draw() and color. Options A, B, and D either use invalid syntax or accept only one protocol.

3. Final Answer:

   func render(item: Drawable & Colorable) { item.draw(); print(item.color) } -> Option C

4. Quick Check:

   Use & to require multiple protocols [OK]

Hint: Use & to require multiple protocols in parameters [OK]

Common Mistakes:

• Using | instead of & for protocol composition
• Accepting only one protocol when both are needed
• Trying to access properties/methods not guaranteed by parameter type