[Solved] Consider this enum with associated values:enum Result { case success(Int), failure(String) }Which switch statement is exhaustive without using a default case? | Swift

Swift - Control Flow

Consider this enum with associated values:

enum Result { case success(Int), failure(String) }

Which switch statement is exhaustive without using a default case?

Aswitch res { case .success(let code): print(code); case .failure(let msg): print(msg) }

Bswitch res { case .failure(let msg): print(msg) }

Cswitch res { case .success(let code): print(code) }

Dswitch res { default: print("\"Unknown\"") }

Step-by-Step Solution

Solution:

Step 1: Identify all enum cases with associated values
Result has two cases: success(Int) and failure(String).
Step 2: Check which switch covers both cases
switch res { case .success(let code): print(code); case .failure(let msg): print(msg) } covers both success and failure cases with associated values, making it exhaustive.
Final Answer:
Switch covering both success and failure cases with associated values. -> Option A
Quick Check:
All associated value cases must be handled [OK]

Quick Trick: Handle all associated value cases explicitly [OK]

Common Mistakes:

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