[Solved] In Swift, what is the primary purpose of using the ?. operator when working with optional values? — Ans: To safely access properties or methods on an optional that might be nil | Swift

Swift - Optionals

In Swift, what is the primary purpose of using the ?. operator when working with optional values?

ATo declare a variable as optional

BTo force unwrap an optional value

CTo safely access properties or methods on an optional that might be nil

DTo convert a non-optional to an optional

Step-by-Step Solution

Solution:

Step 1: Understand optional chaining
The ?. operator allows safe access to properties or methods on an optional without causing a runtime error if the optional is nil.
Step 2: Differentiate from force unwrap
Unlike force unwrapping, it returns nil if the optional is nil instead of crashing.
Final Answer:
To safely access properties or methods on an optional that might be nil -> Option C
Quick Check:
Optional chaining prevents crashes by safely accessing optionals [OK]

Quick Trick: Optional chaining safely accesses optionals without crashing [OK]

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In Swift, what is the primary purpose of using the ?. operator when working with optional values?