[Solved] What will be printed by the following Swift code? var name: String? = "Alice" if let unwrappedName = name { print("Hello, \(unwrappedName)!") } else { print("No name found.") } | Swift

Swift - Optionals

What will be printed by the following Swift code?

var name: String? = "Alice"
if let unwrappedName = name {
    print("Hello, \(unwrappedName)!")
} else {
    print("No name found.")
}

AHello, nil!

BNo name found.

COptional("Alice")

DHello, Alice!

Step-by-Step Solution

Solution:

Step 1: Check the optional value
The variable name contains the string "Alice", not nil.
Step 2: Apply if let unwrapping
Since name has a value, unwrappedName gets "Alice" and prints the greeting.
Final Answer:
Hello, Alice! -> Option D
Quick Check:
Optional with value prints unwrapped string [OK]

Quick Trick: If optional has value, if let block runs [OK]

Common Mistakes:

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