[Solved] Examine this Swift function:func welcome(_ user: String?) { guard let name = user print("Welcome, \(name)!") }What is the issue with this code? | Swift

Swift - Optionals

Examine this Swift function:

func welcome(_ user: String?) {
    guard let name = user
    print("Welcome, \(name)!")
}

What is the issue with this code?

AThe optional <code>user</code> should not be unwrapped with <code>guard let</code>.

BMissing <code>else</code> block after <code>guard let</code> statement.

CThe print statement should be inside the <code>else</code> block.

DThe function should return a value instead of printing.

Step-by-Step Solution

Solution:

Step 1: Check guard let syntax
A guard let statement must always have an else block to handle the nil case.
Step 2: Identify missing else
The code lacks the required else block after guard let name = user.
Final Answer:
Missing else block after guard let statement. -> Option B
Quick Check:
Guard requires else block [OK]

Quick Trick: Guard let always needs an else block [OK]

Common Mistakes:

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