[Solved] Identify the error in this Swift code using nested functions: func calculate() { innerFunc() func innerFunc() { print("Inside inner") } } calculate() | Swift

Swift - Functions

Identify the error in this Swift code using nested functions:

func calculate() {
    innerFunc() 
    func innerFunc() {
        print("Inside inner")
    }
}
calculate()

ANo error, code runs fine

BMissing return type for innerFunc

CinnerFunc cannot be nested inside calculate

DinnerFunc() called before its definition causes error

Step-by-Step Solution

Solution:

Step 1: Analyze function call order
The code calls 'innerFunc()' before it is defined inside 'calculate()'. Swift requires functions to be defined before use.
Step 2: Understand Swift's function declaration rules
Calling a nested function before its declaration causes a compile-time error.
Final Answer:
innerFunc() called before its definition causes error -> Option D
Quick Check:
Call before definition = error [OK]

Quick Trick: Define nested functions before calling them [OK]

Common Mistakes:

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