[Solved] What will be the output of this Swift code?outer: for i in 1...2 { for j in 1...2 { if i == 2 { break outer } print("\(i),\(j)") } } | Swift

Swift - Loops

What will be the output of this Swift code?

outer: for i in 1...2 {
  for j in 1...2 {
    if i == 2 { break outer }
    print("\(i),\(j)")
  }
}

A1,1 1,2

B1,1 1,2 2,1 2,2

C2,1 2,2

DNo output

Step-by-Step Solution

Solution:

Step 1: Analyze the loops and condition
Outer loop runs i=1 to 2; inner loop j=1 to 2. When i==2, break outer loop.
Step 2: Trace output
For i=1, j=1 and j=2 print "1,1" and "1,2". When i=2, break outer loop immediately, so no print.
Final Answer:
1,1 1,2 -> Option A
Quick Check:
Labeled break exits outer loop early [OK]

Quick Trick: Break with label exits outer loop immediately [OK]

Common Mistakes:

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