Bird
Raised Fist0
Svelteframework~3 mins

Why Each blocks ({#each}) in Svelte? - Purpose & Use Cases

Choose your learning style10 modes available
The Big Idea

Discover how a tiny loop can save you hours of tedious work and bugs!

The Scenario

Imagine you have a list of 10 items and you want to show them all on a webpage. You write HTML for each item by hand, and every time the list changes, you have to update the HTML manually.

The Problem

Manually updating each item is slow and easy to mess up. If the list grows or changes often, you waste time rewriting code and risk forgetting to update some parts, causing bugs or inconsistent displays.

The Solution

Svelte's {#each} block lets you write one simple loop that automatically creates HTML for every item in your list. When the list changes, Svelte updates the page for you, saving time and avoiding mistakes.

Before vs After
✗ Before
<ul>\n  <li>Item 1</li>\n  <li>Item 2</li>\n  <li>Item 3</li>\n</ul>
✓ After
<ul>\n  {#each items as item}\n    <li>{item}</li>\n  {/each}\n</ul>
What It Enables

You can easily display and update lists of any size with clean, simple code that stays correct as your data changes.

Real Life Example

Think of a shopping list app where users add or remove items. Using {#each}, the app instantly shows the updated list without you rewriting HTML every time.

Key Takeaways

Manually writing repeated HTML is slow and error-prone.

{#each} automates creating HTML for lists.

This makes your code simpler, cleaner, and easier to maintain.

Practice

(1/5)
1. What does the {#each} block do in Svelte?
easy
A. Creates a conditional statement to show or hide content
B. Repeats a block of HTML for each item in a list
C. Defines a reusable component
D. Declares a reactive variable

Solution

  1. Step 1: Understand the purpose of {#each}

    The {#each} block is used to repeat content for every item in a list or array.
  2. Step 2: Compare with other options

    Options A, C, and D describe other Svelte features, not list repetition.
  3. Final Answer:

    Repeats a block of HTML for each item in a list -> Option B
  4. Quick Check:

    {#each} = repeat list items [OK]
Hint: Remember: {#each} loops over lists [OK]
Common Mistakes:
  • Confusing {#each} with {#if}
  • Thinking it creates components
  • Assuming it declares variables
2. Which of the following is the correct syntax to loop over an array items and display each item in Svelte?
easy
A. {#each items to item} <p>{item}</p> {/each}
B. {#each item in items} <p>{item}</p> {/each}
C. {#each items for item} <p>{item}</p> {/each}
D. {#each items as item} <p>{item}</p> {/each}

Solution

  1. Step 1: Recall Svelte each block syntax

    The correct syntax is {#each array as item} to loop over an array.
  2. Step 2: Check each option

    Only {#each items as item} <p>{item}</p> {/each} uses as correctly. Options A, B, and C use incorrect keywords.
  3. Final Answer:

    {#each items as item} <p>{item}</p> {/each} -> Option D
  4. Quick Check:

    Use as keyword in {#each} [OK]
Hint: Use 'as' keyword: {#each array as item} [OK]
Common Mistakes:
  • Using 'in' instead of 'as'
  • Using 'for' or 'to' keywords
  • Missing the 'as' keyword
3. Given the code:
{`

    {#each fruits as fruit, i}
  • {i}: {fruit}
  • {/each}
`}

What will be the rendered output inside the <ul>?
medium
A.
  • 0: apple
  • 1: banana
  • 2: cherry
  • B.
  • apple: 0
  • banana: 1
  • cherry: 2
  • C.
  • 1: apple
  • 2: banana
  • 3: cherry
  • D.
  • fruit: apple
  • fruit: banana
  • fruit: cherry
  • Solution

    1. Step 1: Understand the each block variables

      The loop uses fruit for the item and i for the index starting at 0.
    2. Step 2: Match output format

      Each list item shows index, colon, then fruit name, so output is 0: apple, 1: banana, 2: cherry.
    3. Final Answer:

      <li>0: apple</li><li>1: banana</li><li>2: cherry</li> -> Option A
    4. Quick Check:

      Index starts at 0, item after colon [OK]
    Hint: Index starts at 0 in {#each items as item, i} [OK]
    Common Mistakes:
    • Confusing index and item order
    • Starting index at 1 instead of 0
    • Using wrong variable names
    4. What is wrong with this Svelte code snippet?
    {`
    
    
      {#each numbers as number}
    • {num}
    • {/each}
    `}
    medium
    A. The variable inside the block should be 'number', not 'num'
    B. The array 'numbers' is not defined
    C. The each block syntax is incorrect
    D. Missing closing {/each} tag

    Solution

    1. Step 1: Check variable names inside each block

      The loop defines number as the item, but inside the block it uses {num}, which is undefined.
    2. Step 2: Verify other syntax parts

      The array is defined, the each block syntax and closing tag are correct.
    3. Final Answer:

      The variable inside the block should be 'number', not 'num' -> Option A
    4. Quick Check:

      Use same variable name inside each block [OK]
    Hint: Use the exact loop variable name inside the block [OK]
    Common Mistakes:
    • Using a different variable name inside the block
    • Forgetting to close the each block
    • Misnaming the array variable
    5. You want to render a list of users with unique IDs and update the list efficiently when users change. Which is the best way to use {#each} with keys in Svelte?
    hard
    A. {#each users as user (user.name)} <p>{user.name}</p> {/each}
    B. {#each users as user} <p>{user.name}</p> {/each}
    C. {#each users as user (user.id)} <p>{user.name}</p> {/each}
    D. {#each users as user (index)} <p>{user.name}</p> {/each}

    Solution

    1. Step 1: Understand keys in each blocks

      Keys help Svelte track items uniquely for efficient updates. The key should be a unique, stable identifier like user.id.
    2. Step 2: Evaluate options

      {#each users as user (user.id)} <p>{user.name}</p> {/each} uses user.id as key, which is best. {#each users as user} <p>{user.name}</p> {/each} has no key, less efficient. {#each users as user (user.name)} <p>{user.name}</p> {/each} uses user.name, which may not be unique. {#each users as user (index)} <p>{user.name}</p> {/each} uses index, which can cause issues when list changes.
    3. Final Answer:

      {#each users as user (user.id)} <p>{user.name}</p> {/each} -> Option C
    4. Quick Check:

      Use unique ID as key in each block [OK]
    Hint: Use unique IDs as keys: {#each items as item (item.id)} [OK]
    Common Mistakes:
    • Not using keys at all
    • Using non-unique keys like names
    • Using index as key causing update bugs
    Recommended

    Ready to prove it?

    Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

    10 questions~5 mineasy hard