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Supabasecloud~10 mins

Generating public URLs in Supabase - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to generate a public URL for a stored file.

Supabase
const { data } = supabase.storage.from('avatars').getPublicUrl([1]);
Drag options to blanks, or click blank then click option'
A'public/profile.png'
B'profile.png'
C'avatars/profile.png'
D'profile/avatar.png'
Attempts:
3 left
💡 Hint
Common Mistakes
Including the bucket name in the file path.
Using incorrect folder names in the path.
2fill in blank
medium

Complete the code to access the public URL from the response.

Supabase
const publicUrl = data.[1];
Drag options to blanks, or click blank then click option'
Aurl
Blink
Cpublic_url
DpublicUrl
Attempts:
3 left
💡 Hint
Common Mistakes
Using snake_case property names.
Trying to access a property that does not exist.
3fill in blank
hard

Fix the error in the code to correctly generate a public URL for a file in a folder.

Supabase
const { data } = supabase.storage.from('documents').getPublicUrl([1]);
Drag options to blanks, or click blank then click option'
A'reports/2023.pdf'
B'2023.pdf'
C'documents/reports/2023.pdf'
D'/reports/2023.pdf'
Attempts:
3 left
💡 Hint
Common Mistakes
Including the bucket name in the file path.
Starting the path with a slash.
4fill in blank
hard

Fill both blanks to generate a public URL and log it to the console.

Supabase
const { data } = supabase.storage.from('images').[1]([2]);
console.log(data.publicUrl);
Drag options to blanks, or click blank then click option'
AgetPublicUrl
B'photos/sunset.jpg'
C'images/sunset.jpg'
Dlist
Attempts:
3 left
💡 Hint
Common Mistakes
Using the bucket name in the file path.
Using the wrong method name.
5fill in blank
hard

Fill all three blanks to generate a public URL for a file and assign it to a variable.

Supabase
const { data } = supabase.storage.from([1]).[2]([3]);
const url = data.publicUrl;
Drag options to blanks, or click blank then click option'
A'avatars'
BgetPublicUrl
C'user123.png'
D'users'
Elist
F'profile/user123.png'
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong bucket names.
Using incorrect method names.
Including bucket name in file path.

Practice

(1/5)
1. What does the getPublicUrl function in Supabase do?
easy
A. It creates a link that anyone can use to access a file in a bucket.
B. It deletes a file from the storage bucket.
C. It uploads a file to the storage bucket.
D. It encrypts a file before storing it.

Solution

  1. Step 1: Understand the purpose of getPublicUrl

    This function is designed to generate a URL that can be shared publicly to access a file stored in Supabase storage.
  2. Step 2: Compare options with function behavior

    Only It creates a link that anyone can use to access a file in a bucket. describes creating a public link. Other options describe unrelated actions like deleting, uploading, or encrypting files.
  3. Final Answer:

    It creates a link that anyone can use to access a file in a bucket. -> Option A
  4. Quick Check:

    Public URL = Link to file [OK]
Hint: Public URLs let anyone access files without login [OK]
Common Mistakes:
  • Confusing URL generation with file upload
  • Thinking it deletes files
  • Assuming it encrypts files automatically
2. Which of the following is the correct way to call getPublicUrl in Supabase to get a public URL for a file named photo.jpg in bucket images?
easy
A. supabase.getPublicUrl('images', 'photo.jpg')
B. supabase.storage.getPublicUrl('images/photo.jpg')
C. supabase.storage.from('images').getPublicUrl('photo.jpg')
D. supabase.storage.from('photo.jpg').getPublicUrl('images')

Solution

  1. Step 1: Recall the correct method chaining

    The correct syntax is to select the bucket first with from('bucket_name'), then call getPublicUrl('file_path').
  2. Step 2: Match options with correct syntax

    supabase.storage.from('images').getPublicUrl('photo.jpg') matches this pattern exactly. Options A, B, and D misuse method calls or argument order.
  3. Final Answer:

    supabase.storage.from('images').getPublicUrl('photo.jpg') -> Option C
  4. Quick Check:

    Bucket then file path = Correct call [OK]
Hint: Use .from(bucket).getPublicUrl(file) syntax [OK]
Common Mistakes:
  • Calling getPublicUrl directly on storage
  • Swapping bucket and file arguments
  • Using wrong method names
3. What will be the output of this code snippet?
const { data } = supabase.storage.from('docs').getPublicUrl('file.txt');
console.log(data.publicUrl);
medium
A. A boolean indicating if the file exists.
B. A string URL to access 'file.txt' publicly in 'docs' bucket.
C. Undefined because 'data' is not returned by getPublicUrl.
D. An error because getPublicUrl returns a promise.

Solution

  1. Step 1: Understand getPublicUrl return value

    The getPublicUrl method returns an object with a publicUrl string property immediately, not a promise.
  2. Step 2: Analyze the console.log output

    Logging data.publicUrl will print the URL string to access the file publicly.
  3. Final Answer:

    A string URL to access 'file.txt' publicly in 'docs' bucket. -> Option B
  4. Quick Check:

    getPublicUrl returns URL string [OK]
Hint: getPublicUrl returns URL object, not a promise [OK]
Common Mistakes:
  • Assuming getPublicUrl is async
  • Expecting undefined data
  • Confusing output with file existence check
4. You tried to generate a public URL with supabase.storage.from('media').getPublicUrl('video.mp4') but got an empty string. What is the most likely cause?
medium
A. getPublicUrl requires an async await call.
B. You forgot to import the Supabase client.
C. The bucket name should be 'videos' not 'media'.
D. The file 'video.mp4' does not exist in the 'media' bucket.

Solution

  1. Step 1: Check file existence in bucket

    If the file does not exist, the public URL generated will be empty or invalid.
  2. Step 2: Evaluate other options

    Importing client or bucket name mismatch would cause errors, not empty string. getPublicUrl is synchronous, so async is not needed.
  3. Final Answer:

    The file 'video.mp4' does not exist in the 'media' bucket. -> Option D
  4. Quick Check:

    Missing file = empty URL [OK]
Hint: Empty URL usually means file missing [OK]
Common Mistakes:
  • Assuming getPublicUrl is async
  • Ignoring file existence
  • Mixing up bucket names
5. You want to share a file publicly but keep other files private in the same bucket. Which approach with Supabase storage and getPublicUrl is best?
hard
A. Use getPublicUrl only on files in a public bucket.
B. Set the bucket to private, then generate public URLs only for specific files using getPublicUrl.
C. Make the entire bucket public so all files are accessible.
D. Upload files with a special tag to mark them public.

Solution

  1. Step 1: Understand bucket privacy settings

    Supabase storage buckets are either public or private. Public buckets allow all files to be accessed via public URLs.
  2. Step 2: Evaluate file-level public access

    Supabase does not support per-file public access in private buckets. To share files publicly, the bucket must be public.
  3. Step 3: Choose best practice

    Use getPublicUrl only on files in a public bucket. correctly states to use getPublicUrl on files in a public bucket to share them. Options A and D are incorrect because file-level public control is not supported. Make the entire bucket public so all files are accessible. makes all files public, which is not desired.
  4. Final Answer:

    Use getPublicUrl only on files in a public bucket. -> Option A
  5. Quick Check:

    Public URLs need public bucket [OK]
Hint: Only public buckets support public URLs per file [OK]
Common Mistakes:
  • Thinking private buckets allow public URLs per file
  • Making whole bucket public without control
  • Assuming tags control public access
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10 questions~5 mineasy hard