Pagination helps show data in small parts instead of all at once. This makes apps faster and easier to use.
Pagination patterns in Supabase
const { data, error } = await supabase
.from('table_name')
.select('*')
.range(fromIndex, toIndex);.range(from, to) fetches rows starting at from index up to to index.
Indexes start at 0, so .range(0, 9) gets the first 10 rows.
const { data, error } = await supabase
.from('products')
.select('*')
.range(0, 9);const { data, error } = await supabase
.from('users')
.select('*')
.range(10, 19);const pageSize = 5; const page = 3; const from = (page - 1) * pageSize; const to = from + pageSize - 1; const { data, error } = await supabase .from('orders') .select('*') .range(from, to);
This program connects to Supabase, defines a function to get a page of data from any table, and fetches the second page of users with 3 users per page. It prints the users to the console.
import { createClient } from '@supabase/supabase-js'; const supabaseUrl = 'https://xyzcompany.supabase.co'; const supabaseKey = 'public-anonymous-key'; const supabase = createClient(supabaseUrl, supabaseKey); async function fetchPage(table, page, pageSize) { const from = (page - 1) * pageSize; const to = from + pageSize - 1; const { data, error } = await supabase .from(table) .select('*') .range(from, to); if (error) { console.error('Error fetching data:', error.message); return []; } return data; } (async () => { const page = 2; const pageSize = 3; const users = await fetchPage('users', page, pageSize); console.log('Users page', page, ':', users); })();
Always check for errors after fetching data to handle problems gracefully.
Use consistent page sizes to keep user experience smooth.
Pagination reduces load and speeds up your app by loading only needed data.
Pagination splits large data into smaller, easy-to-handle parts.
Use .range(from, to) in Supabase to get specific rows.
Calculate indexes carefully to fetch the right page of data.
Practice
.range(from, to) method do in Supabase pagination?Solution
Step 1: Understand the purpose of
This method is used to select a slice of rows by index, starting at.range(from, to)fromand ending atto, inclusive.Step 2: Compare options with this behavior
Only the option stating 'It fetches rows starting from indexfromup to indextoinclusive.' correctly describes the slicing behavior. The other options describe sorting, limiting, or skipping incorrectly.Final Answer:
It fetches rows starting from indexfromup to indextoinclusive. -> Option CQuick Check:
.range(from, to)= fetch rows from-to inclusive [OK]
- Thinking
tois exclusive - Confusing
.rangewith.limit - Assuming it skips rows instead of slicing
.range()?Solution
Step 1: Calculate start and end indexes for page 3
Page 3 means items 21 to 30 (1-based). Since.range()uses 0-based indexes, start = (3-1)*10 = 20, end = 20 + 9 = 29.Step 2: Match calculated range with options
.range(20, 29)matches the correct 0-based slice for page 3.Final Answer:
.range(20, 29) -> Option AQuick Check:
Page 3 with 10 items = indexes 20 to 29 [OK]
- Using 1-based indexes directly
- Off-by-one errors in start or end
- Confusing page number with item count
const page = 2;
const pageSize = 5;
const { data } = await supabase
.from('products')
.select('*')
.range((page - 1) * pageSize, page * pageSize - 1);
How many rows will
data contain?Solution
Step 1: Calculate the range indexes
For page 2 and pageSize 5, start = (2-1)*5 = 5, end = 2*5 - 1 = 9.Step 2: Determine number of rows fetched
Indexes 5 to 9 inclusive means 5 rows (5,6,7,8,9).Final Answer:
5 -> Option DQuick Check:
Range length = end - start + 1 = 5 [OK]
- Counting end index as exclusive
- Miscalculating start or end
- Assuming pageSize is ignored
const page = 1;
const pageSize = 10;
const { data } = await supabase
.from('orders')
.select('*')
.range(page * pageSize, (page + 1) * pageSize - 1);
Why does this return no rows?
Solution
Step 1: Analyze the range calculation
For page 1 and pageSize 10, start = 1*10 = 10, end = (1+1)*10 - 1 = 19. This skips rows 0 to 9.Step 2: Understand why no rows appear
If the table has fewer than 11 rows or you want the first page, you must start at 0. Starting at 10 skips the first 10 rows.Final Answer:
Because the range starts at 10 instead of 0, skipping the first page. -> Option BQuick Check:
Page 1 start index = 0, not 10 [OK]
- Starting range at page * pageSize instead of (page-1)*pageSize
- Misunderstanding zero-based indexing
- Incorrect order of method calls
Solution
Step 1: Define correct zero-based ranges for pages
For 15 items per page, first page is indexes 0 to 14 (15 items). Second page starts at 15 and ends at 29.Step 2: Match options with correct ranges
The option using.range(0, 14)for first page, then.range(15, 29)for second page is correct. It avoids off-by-one errors or overlaps present in the others.Final Answer:
Use.range(0, 14)for first page, then.range(15, 29)for second page. -> Option AQuick Check:
Pages must not overlap and cover all items [OK]
- Overlapping ranges causing duplicate items
- Off-by-one errors in start or end indexes
- Starting second page at wrong index
Ready to prove it?
Pass the test and this pattern moves unknown
