Bird
Raised Fist0
Spring Bootframework~10 mins

@Value for property injection in Spring Boot - Interactive Code Practice

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to inject the property value using @Value annotation.

Spring Boot
import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;

@Component
public class MyComponent {
    @Value("[1]")
    private String appName;
}
Drag options to blanks, or click blank then click option'
A"appName"
B"app.name"
C"${appName}"
D"${app.name}"
Attempts:
3 left
💡 Hint
Common Mistakes
Forgetting to use ${} around the property key.
Using the variable name instead of the property key.
2fill in blank
medium

Complete the code to inject a default value if the property is missing.

Spring Boot
import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;

@Component
public class Config {
    @Value("[1]")
    private String serverPort;
}
Drag options to blanks, or click blank then click option'
A"server.port:8080"
B"${server.port}"
C"${server.port:8080}"
D"server.port"
Attempts:
3 left
💡 Hint
Common Mistakes
Not including the default value syntax with colon.
Using quotes incorrectly around the property key.
3fill in blank
hard

Fix the error in the code to correctly inject an integer property value.

Spring Boot
import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;

@Component
public class ServerConfig {
    @Value("[1]")
    private int maxConnections;
}
Drag options to blanks, or click blank then click option'
A"${server.maxConnections}"
B"${server.maxConnections:100}"
C"server.maxConnections"
D"server.maxConnections:100"
Attempts:
3 left
💡 Hint
Common Mistakes
Omitting the ${} syntax.
Placing default value outside the ${}.
4fill in blank
hard

Fill both blanks to inject a list of strings from a comma-separated property.

Spring Boot
import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;
import java.util.List;

@Component
public class ListConfig {
    @Value("[1]")
    private List<String> servers;

    public List<String> getServers() {
        return servers;
    }
}
Drag options to blanks, or click blank then click option'
A"${servers.list}"
B"${servers.list:}"
C"${servers.list.split(',')}"
D"${servers.list:localhost,127.0.0.1}"
Attempts:
3 left
💡 Hint
Common Mistakes
Not splitting the string to a list.
Missing default value for the property.
5fill in blank
hard

Fill all three blanks to inject a nested property with default and convert it to uppercase.

Spring Boot
import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;

@Component
public class NestedConfig {
    @Value("[1]")
    private String env;

    public String getEnvUpper() {
        return env.[2]().[3]();
    }
}
Drag options to blanks, or click blank then click option'
A"${environment.name:dev}"
BtoLowerCase
CtoUpperCase
Dtrim
Attempts:
3 left
💡 Hint
Common Mistakes
Not using default value in @Value.
Calling methods in wrong order.

Practice

(1/5)
1. What is the main purpose of the @Value annotation in Spring Boot?
easy
A. To create database connections
B. To define a new Spring bean
C. To handle HTTP requests
D. To inject values from configuration files into Spring beans

Solution

  1. Step 1: Understand the role of @Value

    @Value is used to inject configuration values like those from application.properties into Spring beans.
  2. Step 2: Compare with other options

    Defining beans, handling HTTP requests, and database connections are done by other annotations or classes, not @Value.
  3. Final Answer:

    To inject values from configuration files into Spring beans -> Option D
  4. Quick Check:

    @Value injects config values = A [OK]
Hint: Remember: @Value pulls config values into your code [OK]
Common Mistakes:
  • Confusing @Value with @Bean or @Autowired
  • Thinking @Value handles HTTP or DB tasks
  • Ignoring that @Value reads from properties
2. Which of the following is the correct syntax to inject a property named app.name using @Value?
easy
A. @Value(${app.name}) private String appName;
B. @Value("${app.name}") private String appName;
C. @Value("app.name") private String appName;
D. @Value(app.name) private String appName;

Solution

  1. Step 1: Recall correct syntax for property injection

    The property key must be inside ${} and the whole expression inside quotes: @Value("${property.key}").
  2. Step 2: Check each option

    @Value("${app.name}") private String appName; matches the correct syntax. The other options miss either the quotes around the expression, the ${} delimiters, or use quotes around just the property name.
  3. Final Answer:

    @Value("${app.name}") private String appName; -> Option B
  4. Quick Check:

    Correct syntax uses ${} inside quotes = D [OK]
Hint: Use @Value("${property.key}") with quotes and ${} [OK]
Common Mistakes:
  • Omitting quotes around the expression
  • Forgetting the ${} around the property key
  • Using plain property name without ${}
3. Given the property server.port=8080 in application.properties, what will be the output of this Spring component?
public class ServerConfig {
  @Value("${server.port}")
  private int port;

  public int getPort() {
    return port;
  }
}

// In main method:
ServerConfig config = new ServerConfig();
System.out.println(config.getPort());
medium
A. 0
B. 8080
C. null
D. Compilation error

Solution

  1. Step 1: Understand Spring bean lifecycle and injection

    Property injection with @Value happens only when Spring creates and manages the bean. Here, ServerConfig is created manually with new, so injection does not happen.
  2. Step 2: Check default value of int field

    Since port is a primitive int and not injected, it defaults to 0.
  3. Final Answer:

    0 -> Option A
  4. Quick Check:

    Manual new means no injection, int defaults to 0 [OK]
Hint: Only Spring-managed beans get @Value injection [OK]
Common Mistakes:
  • Assuming @Value works on manually created objects
  • Expecting null for primitive int fields
  • Ignoring Spring bean lifecycle
4. What is wrong with this code snippet?
@Value("${missing.property}:defaultValue")
private String value;

When missing.property is not defined in properties, the application fails to start with an error.
medium
A. The field must be public for @Value to work
B. The property key must be defined; default values are not supported
C. The default value syntax is incorrect; colon should be inside quotes
D. The @Value annotation cannot be used on String fields

Solution

  1. Step 1: Check default value syntax in @Value

    The default value must be inside the quotes as part of the expression: @Value("${property:default}") is correct.
  2. Step 2: Identify the error cause

    If the colon is outside quotes or expression is malformed, Spring cannot parse it and throws an error.
  3. Final Answer:

    The default value syntax is incorrect; colon should be inside quotes -> Option C
  4. Quick Check:

    Default values must be inside ${} quotes [OK]
Hint: Put default after colon inside quotes in @Value [OK]
Common Mistakes:
  • Placing colon outside the quotes
  • Assuming default values are not supported
  • Making fields public unnecessarily
5. You want to inject a list of strings from a property app.modes=dev,prod,test into a Spring bean using @Value. Which approach correctly converts the property into a List<String>?
hard
A. @Value("#{T(java.util.Arrays).asList('${app.modes}'.split(','))}") private List<String> modes;
B. @Value("${app.modes}") private List<String> modes; // Spring auto-converts comma-separated string
C. @Value("${app.modes}") private String[] modes; // Use array instead of List
D. @Value("${app.modes}") private String modes; // Parse manually later

Solution

  1. Step 1: Understand property injection for collections

    Spring does not automatically convert comma-separated strings to List<String> with plain @Value.
  2. Step 2: Use SpEL expression for conversion

    @Value("#{T(java.util.Arrays).asList('${app.modes}'.split(','))}") private List<String> modes; uses Spring Expression Language (SpEL) to split the string and convert it to a List<String>, which is the correct approach.
  3. Final Answer:

    @Value("#{T(java.util.Arrays).asList('${app.modes}'.split(','))}") private List<String> modes; -> Option A
  4. Quick Check:

    Use SpEL split and asList for List injection [OK]
Hint: Use SpEL with split and asList to inject List<String> [OK]
Common Mistakes:
  • Expecting automatic conversion from String to List
  • Using array when List is required without conversion
  • Injecting as String and forgetting to parse
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard