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Spring Bootframework~10 mins

application.yml alternative in Spring Boot - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to specify the alternative properties file in Spring Boot.

Spring Boot
spring.config.name=[1]
Drag options to blanks, or click blank then click option'
Aconfig
Bapplication
Csettings
Dproperties
Attempts:
3 left
💡 Hint
Common Mistakes
Using the full file name including extension instead of just the base name.
Trying to set the file path instead of the config name.
2fill in blank
medium

Complete the code to load an alternative properties file from a specific location.

Spring Boot
spring.config.location=[1]
Drag options to blanks, or click blank then click option'
Aclasspath:/config/
Bclasspath:/application/
Chttp://configserver/
Dfile:./config/
Attempts:
3 left
💡 Hint
Common Mistakes
Using classpath: when the file is outside the classpath.
Omitting the prefix and causing Spring Boot to not find the file.
3fill in blank
hard

Fix the error in the command to run Spring Boot with an alternative config file.

Spring Boot
java -jar app.jar --spring.config.name=[1]
Drag options to blanks, or click blank then click option'
Aconfig
Bapplication.yml
Capplication
Dconfig.yml
Attempts:
3 left
💡 Hint
Common Mistakes
Including the file extension in the config name.
Using the default name when trying to override.
4fill in blank
hard

Fill both blanks to specify multiple config locations in Spring Boot.

Spring Boot
spring.config.location=[1],[2]
Drag options to blanks, or click blank then click option'
Aclasspath:/custom/
Bfile:./config/
Cclasspath:/default/
Dfile:/etc/config/
Attempts:
3 left
💡 Hint
Common Mistakes
Using classpath locations when files are outside the classpath.
Not separating locations with commas.
5fill in blank
hard

Fill all three blanks to set an alternative config file name, location, and profile.

Spring Boot
java -jar app.jar --spring.config.name=[1] --spring.config.location=[2] --spring.profiles.active=[3]
Drag options to blanks, or click blank then click option'
Acustomconfig
Bfile:./custom/
Cdev
Dapplication
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing up config name and location values.
Forgetting to activate the profile.

Practice

(1/5)
1. Which file format is a common alternative to application.yml in Spring Boot for configuration?
easy
A. config.ini
B. config.xml
C. settings.json
D. application.properties

Solution

  1. Step 1: Understand Spring Boot configuration files

    Spring Boot supports multiple configuration file formats, but the two most common are application.yml and application.properties.
  2. Step 2: Identify the alternative format

    The application.properties file uses simple key=value pairs and is widely used as an alternative to YAML files.
  3. Final Answer:

    application.properties -> Option D
  4. Quick Check:

    Alternative to application.yml = application.properties [OK]
Hint: Remember: properties files use key=value lines [OK]
Common Mistakes:
  • Confusing XML or JSON as default Spring Boot config
  • Thinking config.ini is supported by Spring Boot
  • Assuming YAML is the only option
2. Which of the following is the correct syntax for setting a server port in application.properties?
easy
A. server.port=8080
B. server.port => 8080
C. server.port : 8080
D. server.port -> 8080

Solution

  1. Step 1: Recall properties file syntax

    In application.properties, each configuration is set as a key=value pair without colons or arrows.
  2. Step 2: Identify the correct key-value format

    The correct syntax uses an equals sign: server.port=8080.
  3. Final Answer:

    server.port=8080 -> Option A
  4. Quick Check:

    Properties syntax uses = not : or arrows [OK]
Hint: Properties files always use key=value format [OK]
Common Mistakes:
  • Using colon instead of equals sign
  • Using arrow symbols which are invalid
  • Mixing YAML syntax with properties syntax
3. Given the following application.properties snippet:
spring.datasource.url=jdbc:mysql://localhost:3306/mydb
spring.datasource.username=root
spring.datasource.password=pass123

What is the effect of this configuration?
medium
A. It sets up a PostgreSQL database connection.
B. It configures a MySQL database connection with the specified URL and credentials.
C. It disables the datasource configuration.
D. It causes a syntax error and fails to start.

Solution

  1. Step 1: Analyze the datasource properties

    The keys spring.datasource.url, username, and password configure the database connection details.
  2. Step 2: Identify the database type and credentials

    The URL contains jdbc:mysql://, indicating a MySQL database with host localhost and database mydb. Username and password are set accordingly.
  3. Final Answer:

    It configures a MySQL database connection with the specified URL and credentials. -> Option B
  4. Quick Check:

    Datasource URL with jdbc:mysql = MySQL config [OK]
Hint: Look for jdbc:mysql in URL to identify MySQL config [OK]
Common Mistakes:
  • Assuming PostgreSQL from MySQL URL
  • Thinking this disables datasource
  • Confusing syntax as error
4. You wrote this in application.properties:
server.port9090

Why does your Spring Boot app fail to start on port 9090?
medium
A. Spaces are not allowed anywhere in properties files.
B. Port 9090 is reserved and cannot be used.
C. Missing equals sign between key and value causes syntax error.
D. Property name is incorrect; should be server.port.number.

Solution

  1. Step 1: Check properties file syntax

    Each line must have a key and value separated by an equals sign (=) or colon (:).
  2. Step 2: Identify the missing equals sign

    The line server.port9090 lacks the equals sign, causing it to be parsed as a single key with no value and preventing the port from being set.
  3. Final Answer:

    Missing equals sign between key and value causes syntax error. -> Option C
  4. Quick Check:

    Properties need key=value format [OK]
Hint: Always use = or : between key and value [OK]
Common Mistakes:
  • Omitting equals sign
  • Using wrong property name
  • Assuming spaces are forbidden everywhere
5. You want to migrate your Spring Boot app configuration from application.yml to application.properties. Which of the following is the correct way to convert this YAML snippet?
server:
  port: 9090
spring:
  datasource:
    url: jdbc:h2:mem:testdb
    username: sa
    password: ""
hard
A. server.port=9090 spring.datasource.url=jdbc:h2:mem:testdb spring.datasource.username=sa spring.datasource.password=
B. server.port : 9090 spring.datasource.url : jdbc:h2:mem:testdb spring.datasource.username : sa spring.datasource.password : ""
C. server.port => 9090 spring.datasource.url => jdbc:h2:mem:testdb spring.datasource.username => sa spring.datasource.password => ""
D. server.port9090 spring.datasource.urljdbc:h2:mem:testdb spring.datasource.usernamesa spring.datasource.password""

Solution

  1. Step 1: Understand YAML to properties conversion

    YAML uses indentation and colons, while properties files use dot notation and equals signs.
  2. Step 2: Convert nested YAML keys to dot notation with =

    The nested keys become dot-separated keys, and values are assigned with equals signs. Empty password is represented by an empty value.
  3. Final Answer:

    server.port=9090 spring.datasource.url=jdbc:h2:mem:testdb spring.datasource.username=sa spring.datasource.password= -> Option A
  4. Quick Check:

    YAML nesting = dot notation + = in properties [OK]
Hint: Convert YAML nesting to dot keys with = [OK]
Common Mistakes:
  • Using colon instead of equals in properties
  • Using arrows or spaces instead of =
  • Not converting nested keys to dot notation
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10 questions~5 mineasy hard