Bird
Raised Fist0
Spring Bootframework~30 mins

Application.properties basics in Spring Boot - Mini Project: Build & Apply

Choose your learning style10 modes available
Application.properties basics
📖 Scenario: You are creating a simple Spring Boot application that needs configuration settings for the server port and application name.
🎯 Goal: Learn how to set up and use the application.properties file to configure basic Spring Boot application properties.
📋 What You'll Learn
Create an application.properties file with specific properties
Add a property for server.port with value 8085
Add a property for spring.application.name with value MyApp
Access these properties in a Spring Boot component using @Value annotation
Print the configured values inside a CommandLineRunner bean
💡 Why This Matters
🌍 Real World
Setting application properties is essential for configuring Spring Boot apps without changing code. It helps manage environments and customize behavior.
💼 Career
Understanding application.properties and property injection is a fundamental skill for Spring Boot developers working on real-world backend services.
Progress0 / 4 steps
1
Create application.properties file with server port
Create an application.properties file and add the line server.port=8085 to set the server port.
Spring Boot
Hint

The application.properties file is where Spring Boot reads configuration values. Setting server.port changes the port your app runs on.

2
Add application name property
In the same application.properties file, add the line spring.application.name=MyApp to set the application name.
Spring Boot
Hint

The spring.application.name property helps identify your app in logs and monitoring.

3
Create a Spring Boot component to read properties
Create a Java class named AppConfigReader annotated with @Component. Use @Value to inject server.port into an int serverPort field and spring.application.name into a String appName field.
Spring Boot
Hint

Use @Value("${property.name}") to inject property values into fields.

4
Print properties using CommandLineRunner
In your main Spring Boot application class, create a CommandLineRunner bean that injects AppConfigReader and prints the serverPort and appName values.
Spring Boot
Hint

Use a CommandLineRunner bean to run code after the app starts. Inject your AppConfigReader to access properties.

Practice

(1/5)
1. What is the primary purpose of the application.properties file in a Spring Boot project?
easy
A. To store configuration settings as key=value pairs
B. To write Java code for the application
C. To define HTML templates for the UI
D. To manage database schema migrations

Solution

  1. Step 1: Understand the role of application.properties

    This file is used to store configuration settings in a simple key=value format.
  2. Step 2: Compare with other options

    Writing Java code, defining HTML templates, or managing database migrations are done elsewhere, not in this file.
  3. Final Answer:

    To store configuration settings as key=value pairs -> Option A
  4. Quick Check:

    Config file = key=value pairs [OK]
Hint: Remember: properties file holds settings, not code or templates [OK]
Common Mistakes:
  • Thinking it contains Java code
  • Confusing it with HTML or template files
  • Assuming it manages database migrations
2. Which of the following is the correct syntax to set the server port to 8081 in application.properties?
easy
A. server.port=8081
B. server-port: 8081
C. server_port=8081
D. port.server=8081

Solution

  1. Step 1: Recall Spring Boot property syntax

    Spring Boot uses dot notation with key=value pairs in application.properties.
  2. Step 2: Identify correct key for server port

    The correct key is server.port, and the value is set with an equals sign.
  3. Final Answer:

    server.port=8081 -> Option A
  4. Quick Check:

    Dot notation + equals sign = correct syntax [OK]
Hint: Use dot notation and equals sign for properties [OK]
Common Mistakes:
  • Using underscores instead of dots
  • Using colon instead of equals sign
  • Swapping key parts order
3. Given this application.properties snippet:
spring.datasource.url=jdbc:mysql://localhost:3306/mydb
spring.datasource.username=root
spring.datasource.password=pass123

What will Spring Boot do with these properties when the app starts?
medium
A. Create a new database named 'mydb'
B. Ignore these properties because they are invalid
C. Start a web server on port 3306
D. Connect to MySQL database at localhost with given credentials

Solution

  1. Step 1: Identify datasource properties

    The keys starting with spring.datasource configure database connection details.
  2. Step 2: Understand Spring Boot behavior

    Spring Boot uses these to connect to the specified MySQL database with username and password.
  3. Final Answer:

    Connect to MySQL database at localhost with given credentials -> Option D
  4. Quick Check:

    Datasource properties = DB connection [OK]
Hint: Datasource keys configure DB connection automatically [OK]
Common Mistakes:
  • Thinking it starts a web server on DB port
  • Assuming properties are ignored
  • Believing it creates the database automatically
4. What is wrong with this application.properties line?
server.port-8080
medium
A. The port number 8080 is invalid
B. The key and value are separated by a dash instead of equals sign
C. The key should be port.server instead
D. There should be no spaces around the dash

Solution

  1. Step 1: Check property syntax

    Properties require key and value separated by an equals sign (=), not a dash (-).
  2. Step 2: Validate the key and value

    The key server.port is correct, and 8080 is a valid port number.
  3. Final Answer:

    The key and value are separated by a dash instead of equals sign -> Option B
  4. Quick Check:

    Use '=' to separate key and value [OK]
Hint: Always use '=' between key and value in properties [OK]
Common Mistakes:
  • Using dash instead of equals sign
  • Swapping key parts order
  • Thinking spaces fix the syntax
5. You want to add a custom property app.title in application.properties and access it in your Spring Boot code. Which of these steps is correct?
hard
A. Add app.title=MyApp in properties and access it with System.getenv("app.title")
B. Add app.title: MyApp in properties and read it with System.getProperty("app.title")
C. Add app.title=MyApp in properties and use @Value("${app.title}") in code
D. Add app.title=MyApp in properties and use @Autowired String app.title in code

Solution

  1. Step 1: Add custom property correctly

    Use key=value syntax: app.title=MyApp in application.properties.
  2. Step 2: Access property in Spring Boot code

    Use @Value("${app.title}") annotation to inject the property value.
  3. Final Answer:

    Add app.title=MyApp in properties and use @Value("${app.title}") in code -> Option C
  4. Quick Check:

    Custom property + @Value injection = correct [OK]
Hint: Use @Value("${key}") to inject properties in code [OK]
Common Mistakes:
  • Using colon instead of equals in properties
  • Trying to get property from environment variables
  • Incorrect use of @Autowired for simple values
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard