StaleElementReferenceException handling in Selenium Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to catch the StaleElementReferenceException.

Selenium Python

from selenium.common.exceptions import [1]

try:
    element.click()
except [1]:
    print("Element is stale, retrying...")

Drag options to blanks, or click blank then click option'

AStaleElementReferenceException

BNoSuchElementException

CTimeoutException

DElementNotInteractableException

Attempts:

3 left

💡 Hint

Common Mistakes

Catching the wrong exception like NoSuchElementException instead of StaleElementReferenceException.

Not importing the exception before using it.

The StaleElementReferenceException is the correct exception to catch when the element is no longer attached to the DOM.

2fill in blank

medium

Complete the code to re-find the element after catching StaleElementReferenceException.

Selenium Python

from selenium.webdriver.common.by import By

try:
    element.click()
except StaleElementReferenceException:
    element = driver.find_element([1], 'submit-button')
    element.click()

Drag options to blanks, or click blank then click option'

ABy.ID

BBy.CLASS_NAME

CBy.XPATH

DBy.NAME

Attempts:

3 left

💡 Hint

Common Mistakes

Using a locator that does not match the element's attribute.

Not re-finding the element after catching the exception.

Using By.ID is a common and reliable way to locate elements by their unique ID attribute.

3fill in blank

hard

Fix the error in the retry loop to handle stale element properly.

Selenium Python

for _ in range(3):
    try:
        element.click()
        break
    except [1]:
        element = driver.find_element(By.ID, 'submit-button')

Drag options to blanks, or click blank then click option'

AElementClickInterceptedException

BTimeoutException

CNoSuchElementException

DStaleElementReferenceException

Attempts:

3 left

💡 Hint

Common Mistakes

Catching the wrong exception causing the retry loop to fail.

Not breaking the loop after successful click.

The retry loop should catch StaleElementReferenceException to re-find the element and retry the click.

4fill in blank

hard

Fill both blanks to create a function that retries clicking an element safely.

Selenium Python

def safe_click(driver, locator):
    for _ in range(3):
        try:
            element = driver.find_element([1], locator)
            element.click()
            return True
        except [2]:
            continue
    return False

Drag options to blanks, or click blank then click option'

ABy.ID

BTimeoutException

CStaleElementReferenceException

DBy.CLASS_NAME

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong locator strategy.

Catching the wrong exception.

The function uses By.ID to find the element and catches StaleElementReferenceException to retry clicking.

5fill in blank

hard

Fill all three blanks to handle stale element exception with explicit wait before retry.

Selenium Python

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

def click_with_wait(driver, locator):
    wait = WebDriverWait(driver, 10)
    for _ in range(3):
        try:
            element = wait.until(EC.element_to_be_clickable(([1], locator)))
            element.click()
            return True
        except [2]:
            import time
            time.sleep([3])
    return False

Drag options to blanks, or click blank then click option'

ABy.ID

BStaleElementReferenceException

C2

DBy.XPATH

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong locator strategy for the wait condition.

Not waiting before retrying after catching the exception.

The function waits for the element located by By.XPATH to be clickable, catches StaleElementReferenceException, and waits 2 seconds before retrying.