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Selenium Pythontesting~10 mins

Find element by partial link text in Selenium Python - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to find an element by partial link text.

Selenium Python
element = driver.find_element_by_[1]("Learn")
Drag options to blanks, or click blank then click option'
Aclass_name
Bid
Cpartial_link_text
Dtag_name
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'id' or 'class_name' instead of 'partial_link_text' to find a link by text.
2fill in blank
medium

Complete the code to click on a link found by partial link text.

Selenium Python
driver.find_element_by_[1]("Contact").[2]()
Drag options to blanks, or click blank then click option'
Asend_keys
Bclick
Cpartial_link_text
Dsubmit
Attempts:
3 left
💡 Hint
Common Mistakes
Using send_keys instead of click to activate the link.
3fill in blank
hard

Fix the error in the code to correctly find an element by partial link text.

Selenium Python
element = driver.find_element_by_[1]("About Us")
Drag options to blanks, or click blank then click option'
Apartial_link_text
Blink_text
Cxpath
Dcss_selector
Attempts:
3 left
💡 Hint
Common Mistakes
Using link_text when partial matching is needed.
4fill in blank
hard

Fill both blanks to create a dictionary comprehension that finds elements by partial link text and stores their texts.

Selenium Python
links_text = {el.text: el for el in driver.find_elements_by_[1]("[2]")}
Drag options to blanks, or click blank then click option'
Apartial_link_text
BContact
CAbout
Dlink_text
Attempts:
3 left
💡 Hint
Common Mistakes
Using link_text instead of partial_link_text for partial matches.
Using full link text instead of partial text.
5fill in blank
hard

Fill all three blanks to filter links by partial link text and check if their text length is greater than 5.

Selenium Python
filtered_links = [el for el in driver.find_elements_by_[1]("[2]") if len(el.text) [3] 5]
Drag options to blanks, or click blank then click option'
Apartial_link_text
BContact
C>
D==
Attempts:
3 left
💡 Hint
Common Mistakes
Using link_text instead of partial_link_text.
Using wrong comparison operators like '<' or '==' instead of '>'.

Practice

(1/5)
1. What does the Selenium method find_element_by_partial_link_text do?
easy
A. Finds a link element containing the specified partial text.
B. Finds any element with the exact text match.
C. Finds elements by their HTML tag name.
D. Finds elements by their CSS class name.

Solution

  1. Step 1: Understand the method purpose

    The method find_element_by_partial_link_text searches for <a> elements that contain the given text partially.
  2. Step 2: Compare with other locator methods

    Unlike exact text match or tag name search, this method matches any link containing the partial text.
  3. Final Answer:

    Finds a link element containing the specified partial text. -> Option A
  4. Quick Check:

    Partial link text = Finds links with partial text [OK]
Hint: Partial link text finds links by part of their visible text [OK]
Common Mistakes:
  • Confusing partial link text with exact text match
  • Using it on non-link elements
  • Expecting it to find by attribute instead of visible text
2. Which of the following is the correct syntax to find a link containing the text "Login" using Selenium in Python?
easy
A. driver.find_element_by_partial_link_text['Login']
B. driver.find_element_by_partial_link_text(Login)
C. driver.find_element_by_partial_link_text("Login")
D. driver.find_element_by_partial_link_text{Login}

Solution

  1. Step 1: Check method usage and argument format

    The method requires a string argument inside parentheses and quotes, like "Login".
  2. Step 2: Validate Python syntax

    driver.find_element_by_partial_link_text("Login") uses correct parentheses and quotes. Options A, B, and D have syntax errors or wrong brackets.
  3. Final Answer:

    driver.find_element_by_partial_link_text("Login") -> Option C
  4. Quick Check:

    Correct method call uses parentheses and quotes [OK]
Hint: Use parentheses and quotes for string argument in method call [OK]
Common Mistakes:
  • Omitting quotes around the string
  • Using square or curly brackets instead of parentheses
  • Passing variable without quotes
3. What will the following code print if the page has a link with text "Click here to Login"?
element = driver.find_element_by_partial_link_text("Login")
print(element.text)
medium
A. NoSuchElementException
B. Login
C. Click here
D. Click here to Login

Solution

  1. Step 1: Understand partial link text matching

    The method finds the first link containing "Login" anywhere in its visible text.
  2. Step 2: Check what element.text returns

    It returns the full visible text of the found link, which is "Click here to Login".
  3. Final Answer:

    Click here to Login -> Option D
  4. Quick Check:

    Partial match finds full link text [OK]
Hint: Partial link text finds full link text, not just the partial part [OK]
Common Mistakes:
  • Expecting only the partial text to print
  • Assuming it throws exception if partial matches
  • Confusing element.text with attribute values
4. Given this code snippet, what is the error and how to fix it?
element = driver.find_element_by_partial_link_text(Login)
print(element.text)
medium
A. SyntaxError due to missing parentheses; fix by adding parentheses
B. NameError because Login is not quoted; fix by adding quotes: "Login"
C. NoSuchElementException because partial link text is incorrect
D. TypeError because find_element_by_partial_link_text expects int

Solution

  1. Step 1: Identify the error in argument usage

    The argument Login is not in quotes, so Python treats it as a variable, causing NameError.
  2. Step 2: Correct the argument to a string

    Wrap Login in quotes like "Login" to pass a string literal.
  3. Final Answer:

    NameError because Login is not quoted; fix by adding quotes: "Login" -> Option B
  4. Quick Check:

    String arguments need quotes [OK]
Hint: Always quote string arguments in Selenium locators [OK]
Common Mistakes:
  • Forgetting quotes around string literals
  • Assuming partial link text accepts variables without quotes
  • Misreading error type as syntax error
5. You want to click a link that contains either "Sign" or "Register" in its text. Which approach correctly finds and clicks the link using Selenium in Python?
hard
A. Try finding by partial link text "Sign" first, if not found, then try "Register".
B. Use find_element_by_partial_link_text("Sign or Register") to find either.
C. Use CSS selector to find links containing "Sign" or "Register" text.
D. Use find_element_by_link_text("Sign Register") to find combined text.

Solution

  1. Step 1: Understand partial link text limitation

    The method matches only one partial string at a time; it cannot match multiple alternatives in one call.
  2. Step 2: Implement fallback logic

    Try finding link with "Sign" first; if not found, catch exception and try "Register" next.
  3. Final Answer:

    Try finding by partial link text "Sign" first, if not found, then try "Register". -> Option A
  4. Quick Check:

    Partial link text matches one string; use fallback for multiple options [OK]
Hint: Try partial link texts one by one for multiple options [OK]
Common Mistakes:
  • Using 'or' inside partial link text string
  • Expecting one call to match multiple partial texts
  • Using link_text instead of partial_link_text for partial matches
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10 questions~5 mineasy hard